中int8_t，int_least8_t和int_fast8_t的区别？

问题描述

有什么INT类型之间的中int8_t ， int_least8_t 和 int_fast8_t ？

What is the difference between the int types int8_t, int_least8_t and int_fast8_t?

推荐答案

的差额，C99标准卡尔Norum时引述的部分定义。但它可能是有一个例子是有用的。

The difference is defined in the sections of the C99 standard that Carl Norum quoted. But it may be useful to have an example.

假设你有一个36位系统中的C编译器，以字符 = 9位，短 = 18位， INT = 36位，而长 = 72位。然后

Suppose you have a C compiler for a 36-bit system, with char = 9 bits, short = 18 bits, int = 36 bits, and long = 72 bits. Then

• 中int8_t 的不存在的，因为没有办法满足其的究竟的8值位的约束没有填充。


• int_least8_t 是字符的一个typedef。不是的短或 INT ，因为标准要求的最小的类型至少有8个位。


• int_fast8_t 可以是任何东西。这很可能是 INT 的一个typedef如果本地大小被认为是快。

• int8_t does not exist, because there is no way to satisfy the constraint of having exactly 8 value bits with no padding.
• int_least8_t is a typedef of char. NOT of short or int, because the standard requires the smallest type with at least 8 bits.
• int_fast8_t can be anything. It's likely to be a typedef of int if the "native" size is considered to be "fast".

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