解析json字符串时无法识别的字段

解析json字符串时无法识别的字段

本文介绍了解析json字符串时无法识别的字段,未标记为可忽略的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在研究泽西岛休息服务。试图传递一个通用对象(在我的情况下是AppObject)作为发布请求,来自服务器的响应也是通用对象(在我的案例中是AppObject)我期待一个string {license:12345,list:[{alternateId:AlternateID,classificati on:1}]} 但是列表的内容我正在获得 dimRequirement ,如下所示。所以当解析json时我得到了异常。有没有办法将它作为列表本身而无需更改代码。或者任何人都可以帮助我。

I am working on a Jersey rest services. trying to pass a generic object(in my case AppObject) as post request and the response from the server is also the generic object(in my case AppObject) i am expecting a string {"license":"12345","list":[{"alternateId":"AlternateID","classificati‌​on":"1"}] } but insted of list i am getting dimRequirement as shown below. So when parsing the json am getting the exception. Is there a way to get it as list itself with out changing the code. Or any alternative could anybody help me.

在客户端接收Json字符串

{"license":"12345","dimRequirement":[{"alternateId":"AlternateID","classificati‌​on":"1"}] }

我的客户

AppObject<DimRequirement> appObject = new AppObject<DimRequirement>();
        appObject.setClientKey(4L);
        Client client = Client.create();
        WebResource webResource = client
                   .resource("http://localhost:8080/myproject/");

        JSONObject json = new JSONObject(appObject);
        ClientResponse response = webResource.path("rest").path("requirement/getreq").type("application/json").accept("application/json")
                .post(ClientResponse.class,json.toString());
        String output = response.getEntity(String.class);
        System.out.println(output);
        appObject= new ObjectMapper().readValue(
                output, AppObject.class);

错误

   Unrecognized field "dimRequirement" (Class com.vxl.AppObject), not marked as ignorable
at [Source: java.io.StringReader@7be6f06c; line: 1, column: 49] (through reference chain: com.vxl.appanalytix.AppObject["dimRequirement"])
    at org.codehaus.jackson.map.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:53)
    at org.codehaus.jackson.map.deser.StdDeserializationContext.unknownFieldException(StdDeserializationContext.java:244)
    at org.codehaus.jackson.map.deser.StdDeserializer.reportUnknownProperty(StdDeserializer.java:589)
    at org.codehaus.jackson.map.deser.StdDeserializer.handleUnknownProperty(StdDeserializer.java:575)
    at org.codehaus.jackson.map.deser.BeanDeserializer.handleUnknownProperty(BeanDeserializer.java:684)
    at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:515)
    at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:351)
    at org.codehaus.jackson.map.ObjectMapper._readMapAndClose(ObjectMapper.java:2131)
    at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1402)
    at com.vxl.CheckJersy.main(CheckJersy.java:56)

通用类

@XmlRootElement
@XmlSeeAlso({DimRequirement.class })
public class AppObject<T> implements Serializable {

    private List<T> list;
    private Long clientKey;

    public AppObject() {
        list = new ArrayList<T>();

    }

    public AppObject(List<T> list) {
        this.list = list;
    }

    @XmlAnyElement(lax = true)
    public List<T> getList() {
        return list;
    }

    public void setList(List<T> list) {
        this.list = list;
    }

    public Long getClientKey() {
    return clientKey;
}

public void setClientKey(Long clientKey) {
    this.clientKey = clientKey;
}

}

服务

@Path("/requirement")
public class DimRequirementManagerImpl {
@POST
    @Consumes({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON })
    @Produces({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON })
    @Path("/getreq")
    @Override
    public AppObject getAllByClientNIsCurrent(
            AppObject<DimRequirement> appObj) {
        List<DimRequirement> dimreqlist = dimRequirementDao
                .getAllByClientNIsCurrent(appObj.getClientKey());
        AppObject appObject = new AppObject();
        appObject.setList(dimreqlist);
        return appObject;
    }}

设置为AppObject的DimRequirement

@XmlRootElement
public class DimRequirement extends BaseObject implements Serializable {
private Long requirementKey;
private String description;
private String priority;
@Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    @Column(name="requirementKey")
    public Long getRequirementKey() {
        return this.requirementKey;
    }
    public void setRequirementKey(Long requirementKey) {
        this.requirementKey = requirementKey;
    }
 @Column(name="Description")
    public String getDescription() {
        return this.description;
    }
    public void setDescription(String description) {
        this.description = description;
    }
 @Column(name="Priority")
    public String getPriority() {
        return this.priority;
    }
    public void setPriority(String priority) {
        this.priority = priority;
    }
}


推荐答案

i已将服务的返回类型更改为字符串(json字符串)。

i have changed the return type of service to string(json string).

服务

@Path("/requirement")
public class DimRequirementManagerImpl {
@POST
@Consumes({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON })
@Produces({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON })
@Path("/getreq")
@Override
public String getAllByClientNIsCurrent(AppObject<DimRequirement> appObj) {
try {
     List<DimRequirement> dimreqlist = dimRequirementDao.getAllByClientNIsCurrent(appObj.getClientKey());
     AppObject appObject = new AppObject();
     appObject.setList(dimreqlist);
     JSONObject jsonget = new JSONObject(appObject);
     return jsonget.toString();
     }catch (Exception e) {
        AppObject<DimRequirement> appObject = new AppObject<DimRequirement>();
        appObject.setLicense("12345");
        JSONObject jsonget = new JSONObject(appObject);
        return jsonget.toString();
    }
}}

这适用于问题returnig中的同一客户json {license:12345,list:[{alternateId:AlternateID,classificati on:1}}}

this worked for the same client in the question returnig json {"license":"12345","list":[{"alternateId":"AlternateID","classificati‌​on":"1"}] }

客户

 AppObject<DimRequirement> appObject = new AppObject<DimRequirement>();
        appObject.setClientKey(4L);
        Client client = Client.create();
        WebResource webResource = client
                   .resource("http://localhost:8080/myproject/");

        JSONObject json = new JSONObject(appObject);
        ClientResponse response = webResource.path("rest").path("requirement/getreq").type("application/json").accept("application/json")
                .post(ClientResponse.class,json.toString());
        String output = response.getEntity(String.class);
       AppObject<DimRequirement> appObjectclientns = new ObjectMapper()
                .readValue(output,
                        new TypeReference<AppObject<DimRequirement>>() {
                        });

这篇关于解析json字符串时无法识别的字段,未标记为可忽略的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-29 17:56