问题描述
我有逗号分隔的正则表达式列表:
I have comma separated list of regular expressions:
.{8},[0-9],[^0-9A-Za-z ],[A-Z],[a-z]
我对逗号做了一个拆分.现在我正在尝试将此正则表达式与生成的密码进行匹配.问题是Pattern.compile 不喜欢没有转义的方括号.
I have done a split on the comma. Now I'm trying to match this regex against a generated password. The problem is that Pattern.compile does not like square brackets that is not escaped.
请给我一个简单的函数，它接受一个像这样的字符串:[0-9] 并返回转义的字符串 \[0-9\].
Can some please give me a simple function that takes a string like so: [0-9] and returns the escaped string \[0-9\].
推荐答案
您可以使用 Pattern.quote(String).
You can use Pattern.quote(String).
来自文档:
public static String quote (String s)
返回指定String的文字模式String.
此方法生成一个字符串，该字符串可用于创建一个模式，该模式将匹配字符串 s，就好像它是一个文字模式一样.
This method produces a String that can be used to create a Pattern that would match the string s as if it were a literal pattern.
输入序列中的元字符或转义序列将没有特殊含义.
Metacharacters or escape sequences in the input sequence will be given no special meaning.
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