生成地图＆LT;字符串，字符串＆GT;从POJO

问题描述

我有一个POJO，和（目前还未建）类，将返回它的列表。我想自动生成必要的POJO进行访问，地图上的code。这是一个好主意，是有可能自动做的，我需要手动为每一个POJO我想治疗这种方式做到这一点？

I have a POJO, and a (currently not-yet-built) class that will return Lists of it. I'd like to automatically generate the code necessary for the POJO to be accessed as a Map. Is this a good idea, is it possible to do automatically, and do I need to do this manually for every POJO I want to treat this way?

谢谢，刘德华

推荐答案

您可以使用共享的beanutils <$c$c>BeanMap对于这一点。

You can use Commons BeanUtils BeanMap for this.

Map map = new BeanMap(someBean);

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更新：因为这不是一种选择，由于Android的一些明显的库相关问题，这里有一个基本的开球例如你怎么可以用的：

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Update: since that's not an option due to some apparent library dependency problems in Android, here's a basic kickoff example how you could do it with little help of Reflection API:

public static Map<String, Object> mapProperties(Object bean) throws Exception {
    Map<String, Object> properties = new HashMap<String, Object>();
    for (Method method : bean.getClass().getDeclaredMethods()) {
        if (Modifier.isPublic(method.getModifiers())
            && method.getParameterTypes().length == 0
            && method.getReturnType() != void.class
            && method.getName().matches("^(get|is).+")
        ) {
            String name = method.getName().replaceAll("^(get|is)", "");
            name = Character.toLowerCase(name.charAt(0)) + (name.length() > 1 ? name.substring(1) : "");
            Object value = method.invoke(bean);
            properties.put(name, value);
        }
    }
    return properties;
}

我不知道，如果<$c$c>java.beans API是在Android中使用，但如果是真的，那么你可以取代

I am not sure if java.beans API is available in Android, but if true, then you could replace

name = Character.toLowerCase(name.charAt(0)) + (name.length() > 1 ? name.substring(1) : "");

按

name = Introspector.decapitalize(name);

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