HttpsURLConnection的间歇性故障同一网址

问题描述

我想我遇到了同样的
结果
这是Android 1.5的SDK。
我碰巧打电话低于code（这是一种方法）有几次
相同的URL，并间歇性失败。结果
当它失败了，没有异常，流是空故
readConnection失败，GETRESPONSE code返回-1。结果
全球禁用缓存，setDefaultUseCaches（假）;

我想一定有某种URL连接对象池的地方。

我如何能解决这个任何想法？

  HttpURLConnection的连接= NULL;
    尝试{
        网址URL =新的URL（this.url）;
        连接=（HttpURLConnection类）url.openConnection（）;
        connection.setRequestProperty（授权，基本+
        Base64编码coder.en codeString的（用户+：+密码））;
        connection.setRequestProperty（用户代理的userAgent）;
        connection.connect（）;        readConnection（connection.getInputStream（））;        connection.disconnect（）;
    }赶上（IOException异常前）{
               reportException（例如，connection.getResponse code（））
    }赶上（ParserException前）{
               reportException（例如，connection.getResponse code（））
    }
 

解决方案

我解决这个问题的方法是添加以下行...

  System.setProperty（http.keepAlive，假）;
 

...我的连接线之前...

 连接=（HttpURLConnection类）url.openConnection（）;
 

祝你好运！

I think I'm experiencing the same ashttp://groups.google.com/group/android-developers/msg/9d37d64aad0ee357
This is Android 1.5 SDK.I happen to call several times below code(which is in a method) withthe same url and it fails intermittently.
When it fails, there is no exception, the stream is empty so thereadConnection fails, and getResponseCode returns -1.
Global caching is disabled, setDefaultUseCaches(false);

I suppose there must be some kind of url connection object pool somewhere.

Any idea on how can I workaround this?

HttpURLConnection connection = null;
    try {
        URL url = new URL(this.url);
        connection = (HttpURLConnection) url.openConnection();
        connection.setRequestProperty("Authorization", "basic " +
        Base64Coder.encodeString(user + ":" + password));
        connection.setRequestProperty("User-Agent", userAgent);
        connection.connect();

        readConnection(connection.getInputStream());

        connection.disconnect();
    } catch (IOException ex) {
               reportException(ex, connection.getResponseCode())
    } catch (ParserException ex) {
               reportException(ex, connection.getResponseCode())
    }

解决方案

The way I fixed this issue was to add the below line...

System.setProperty("http.keepAlive", "false");

...before my connection line...

connection = (HttpURLConnection) url.openConnection();

Good luck!

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