如何在FXML Controller中获取父窗口?

问题描述

例如，我想在单击按钮时打开DirectoryChooser:

For example, I want open a DirectoryChooser when clicking on the button:

<VBox fx:controller="com.foo.MyController"
    xmlns:fx="http://javafx.com/fxml">
    <children>
        <Button text="Click Me!" onAction="#handleButtonAction"/>
    </children>
</VBox>

和Controller类:

And the Controller class:

package com.foo;

public class MyController {
    public void handleButtonAction(ActionEvent event) {
        DirectoryChooser dc = new DirectoryChooser();
        File folder = dc.showDialog(null);//I want to put the WIndows here.
    }
}

我想将主窗口放到 ShowDialog 中，以便将其阻止，但是如何访问它?

I want to put the main Window to the ShowDialog so that it will be blocked but how can I access it?

推荐答案

您可以向任何节点请求Scene，然后调用Scene#getWindow().

you can ask any node for the Scene and then call Scene#getWindow().

例如((Node)event.getTarget()).getScene().getWindow()

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