本文介绍了未捕获的类型错误:无法使用网站读取 null 的属性“uid"的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想将注册用户的详细信息从 firestore 获取到 html 页面中.当用户单击我的个人资料页面时,它会导航到下一个 html 页面,其中包含名字和姓氏等字段.此字段已在注册页面时输入.所以我想从 firestore 获取这些详细信息到下一个 html 页面.但是我收到了无法读取 null 的属性 'uid'"之类的错误.如何解决这个问题,这是我的 html 页面:
<html lang="zh-cn"><头>deyaPay</title><meta charset="utf-8"><meta name="viewport" content="width=device-width, initial-scale=1,shrink-to-fit=no"><script src="https://www.gstatic.com/firebasejs/4.6.2/firebase-app.js"></script><script src="https://www.gstatic.com/firebasejs/4.6.2/firebase-auth.js"></script><script src="https://code.jquery.com/jquery-3.2.1.slim.min.js"></script><script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.6/umd/popper.min.js"></script><script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-beta.2/js/bootstrap.min.js"></script><script src="https://www.gstatic.com/firebasejs/4.6.2/firebase-firestore.js"></script><link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-beta.2/css/bootstrap.min.css"integrity="sha384-PsH8R72JQ3SOdhVi3uxftmaW6Vc51MKb0q5P2rRUpPvrszubwgT"crossori><脚本>变量配置 = {apiKey: "AizaSyAJsAstiMsrB2QGJyoqiTELw0vsWFVVahw",authDomain: "websignin-79fec.firebaseapp.com",databaseURL: "https://websignin-79fec.firebaseio.com",projectId: "websignin-79fec",存储桶:"",messagesSenderId:480214472501"};firebase.initializeApp(config);<script src="https://www.gstatic.com/firebasejs/4.6.2/firebase-firestore.js"></script><link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-beta.2/css/bootstrap.min.css"integrity="sha384-PsH8R72JQ3SOdhVi3uxftmaW6Vc51MKb0q5P2rRUpPvrszubwgT"crossori><风格>//css 在这里..</风格><script type="text/javascript">函数 myProfile() {var user = firebase.auth().currentUser.uid;var db = firebase.firestore();var docRef = db.collection("deyaPayusers").doc(user);docRef.get().then(function(doc) {if(doc && doc.exists) {const myData = doc.data();const ffname = myData.FirstName;const llname = myData.LastName;const phonen = myData.PhoneNumber;document.getElementById("fname").value = ffname;document.getElementById("lname").value = llname;document.getElementById("phone").value = phonen;}}).catch(函数(错误){console.log("出现错误:",error);});}头部><body onload='myProfile()'><div class="登录表单"><form method="post"><h2>个人资料</h2><div class="form-group"><input type="text" name="firstname" id="fnmae" placeholder="FirstName" class="form-control" >