如何设置Swagger在

如何设置Swagger在

本文介绍了如何设置Swagger在@Asynchronous jax-rs bean方法中忽略@Suspended AsyncResponse?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

Swagger-Core似乎将@Suspended的AsyncResponse asyncResponse成员解释为请求身份参数。这显然是不是意图和情况。

Swagger-Core seems to interpret the @Suspended final AsyncResponse asyncResponse member as request body param. This is clearly not intended nor the case.

我想告诉swagger-core忽略这个参数,并将其从api-docs中排除。任何想法?

I would like to tell swagger-core to ignore this parameter and to exclude it from the api-docs. Any ideas?

这是我的代码如下:

@Stateless
@Path("/coffee")
@Api(value = "/coffee", description = "The coffee service.")
public class CoffeeService
{
    @Inject
    Event<CoffeeRequest> coffeeRequestListeners;

    @GET
    @ApiOperation(value = "Get Coffee.", notes = "Get tasty coffee.")
    @ApiResponses({
            @ApiResponse(code = 200, message = "OK"),
            @ApiResponse(code = 404, message = "Beans not found."),
            @ApiResponse(code = 500, message = "Something exceptional happend.")})
    @Produces("application/json")
    @Asynchronous
    public void makeCoffee( @Suspended final AsyncResponse asyncResponse,

                             @ApiParam(value = "The coffee type.", required = true)
                             @QueryParam("type")
                             String type)
    {
        coffeeRequestListeners.fire(new CoffeeRequest(type, asyncResponse));
    }
}






更新:基于答案的解决方案




Update: Solution based on Answer

public class InternalSwaggerFilter implements SwaggerSpecFilter
{
    @Override
    public boolean isOperationAllowed(Operation operation, ApiDescription apiDescription, Map<String, List<String>> stringListMap, Map<String, String> stringStringMap, Map<String, List<String>> stringListMap2) {
        return true;
    }

    @Override
    public boolean isParamAllowed(Parameter parameter, Operation operation, ApiDescription apiDescription, Map<String, List<String>> stringListMap, Map<String, String> stringStringMap, Map<String, List<String>> stringListMap2) {
        if( parameter.paramAccess().isDefined() && parameter.paramAccess().get().equals("internal") )
            return false;
        return true;
    }
}







FilterFactory.setFilter(new InternalSwaggerFilter());






修改示例代码片段




Revised Example Code Fragment

...
@Asynchronous
public void makeCoffee( @Suspended @ApiParam(access = "internal") final AsyncResponse asyncResponse,...)
...


推荐答案

我想你必须使用过滤器。
以下是

I think you have to use filters.Here is an example https://github.com/wordnik/swagger-core/issues/269

可以在java中编码。

Could be coded in java too.

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07-29 10:55