在AWS S3 CLI中选择文件下载

问题描述

我在S3存储桶中有文件，我试图基于8月8日，9月9日这样的日期下载文件，如何下载选择性的日期文件?我使用了以下代码，但仍会下载整个存储段列表

I have files in S3 bucket, I was trying to download files based on date like 08th aug, 09th Aug, how can I download selective date file?.I used following code but it still downloads entire bucket list

aws s3 cp s3://bucketname/ folder/file --profile pname --exclude \"*\" --recursive --include \"" + "2015-08-09" + "*\"

我不确定如何实现这一目标.

I am not sure, how to achieve this.

推荐答案

此命令将复制以2015-08-15开头的所有文件:

This command will copy all files starting with 2015-08-15:

aws s3 cp s3://BUCKET/ folder --exclude "*" --include "2015-08-15*" --recursive

如果您的目标是同步一组文件而不复制两次，请使用sync命令:

If your goal is to synchronize a set of files without copying them twice, use the sync command:

aws s3 sync s3://BUCKET/ folder

这将复制自上次同步以来已添加或修改的所有文件.

That will copy all files that have been added or modified since the previous sync.

实际上，这等效于上面的cp命令:

In fact, this is the equivalent of the above cp command:

aws s3 sync s3://BUCKET/ folder --exclude "*" --include "2015-08-15*"

参考文献:

• AWS CLI s3 sync命令文档
• AWS CLI s3 cp命令文档

• AWS CLI s3 sync command documentation
• AWS CLI s3 cp command documentation

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