Java中两个具有相同名称的方法

问题描述

我注意到，如果我有两个同名方法，当我用SomeOtherObject调用方法时，第一个方法接受SomeObject，第二个方法接受扩展SomeObject的对象，它会自动使用仅接受SomeObject.如果我将SomeOtherObject强制转换为SomeObject，则即使对象是SomeOtherObject的实例，也会使用接受SomeObject的方法.这意味着在编译时选择了该方法.为什么?

I noticed that if I have two methods with the same name, the first one accepts SomeObject and the second one accepts an object extending SomeObject when I call the method with SomeOtherObject, it automatically uses the one that only accepts SomeObject. If I cast SomeOtherObject to SomeObject, the method that accepts SomeObject is used, even if the object is an instanceof SomeOtherObject. This means the method is selected when compiling. Why?

推荐答案

这就是Java中方法重载解析的工作方式:该方法是在编译时选择的.

That's how method overload resolution in Java works: the method is selected at compile time.

有关所有丑陋的详细信息，请参见 Java语言规范§ 15.12.

For all of the ugly details, see the Java Language Specification §15.12.

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