问题描述
我想将以新的Swift Package Manager格式编写的Swift代码编译为高度优化的二进制代码.当前可以使用swiftc -O somefile.swift来实现，但是由于swift软件包是使用swift build命令构建的，因此我无法通过-O选项，因为它不接受.那么有没有一种方法可以指定在编译过程中优化代码?
I want to compile my swift code written in the new Swift Package Manager format into highly optimized binary code. This is possible currently using swiftc -O somefile.swift But since the swift packages are built using swift build command, I cannot pass -O option as it does not accept it. So is there a way to specify to optimize the code during the compile process?
推荐答案
您可以使用以下版本构建发布配置:swift build --configuration release.
You can build in a release configuration with: swift build --configuration release.
您还可以通过以下方式查看工具的使用情况:
You can also see the tool usage via:
$ swift build --help
OVERVIEW: Build sources into binary products
USAGE: swift build [mode] [options]
MODES:
-c, --configuration <value> Build with configuration (debug|release) [default: debug]
--clean [<mode>] Delete artifacts (build|dist) [default: build]
OPTIONS:
-C, --chdir <path> Change working directory before any other operation
--build-path <path> Specify build/cache directory [default: ./.build]
--color <mode> Specify color mode (auto|always|never) [default: auto]
-v, --verbose Increase verbosity of informational output
-Xcc <flag> Pass flag through to all C compiler invocations
-Xlinker <flag> Pass flag through to all linker invocations
-Xswiftc <flag> Pass flag through to all Swift compiler invocations
NOTE: Use `swift package` to perform other functions on packages
列出了此选项.
请参阅程序包管理器参考了解更多信息.
See the package manager reference for more information.
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