本文介绍了按组拆分列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一些数据看起来有点像这样:
I have some data that looks a little bit like this:
test.frame <- read.table(text = "name amounts
JEAN 318.5,45
GREGORY 1518.5,67,8
WALTER 518.5
LARRY 518.5,55,1
HARRY 318.5,32
",header = TRUE,sep = "")
我希望看起来更像这样...
I'd like it to look more like this ...
name amount
JEAN 318.5
JEAN 45
GREGORY 1518.5
GREGORY 67
GREGORY 8
WALTER 518.5
LARRY 518.5
LARRY 55
LARRY 1
HARRY 318.5
HARRY 32
似乎应该有一个直截了当的方法来打破金额列,但我没有想出它。很高兴为此特定命令的RTFM页面答案。我正在寻找什么命令?
It seems like there should be a straightforward way to break out the "amounts" column, but I'm not coming up with it. Happy to take a "RTFM page for this particular command" answer. What's the command I'm looking for?
推荐答案
(test.frame <- read.table(text = "name amounts
JEAN 318.5,45
GREGORY 1518.5,67,8
WALTER 518.5
LARRY 518.5,55,1
HARRY 318.5,32
",header = TRUE,sep = ""))
# name amounts
# 1 JEAN 318.5,45
# 2 GREGORY 1518.5,67,8
# 3 WALTER 518.5
# 4 LARRY 518.5,55,1
# 5 HARRY 318.5,32
tmp <- setNames(strsplit(as.character(test.frame$amounts),
split = ','), test.frame$name)
data.frame(name = rep(names(tmp), sapply(tmp, length)),
amounts = unlist(tmp), row.names = NULL)
# name amounts
# 1 JEAN 318.5
# 2 JEAN 45
# 3 GREGORY 1518.5
# 4 GREGORY 67
# 5 GREGORY 8
# 6 WALTER 518.5
# 7 LARRY 518.5
# 8 LARRY 55
# 9 LARRY 1
# 10 HARRY 318.5
# 11 HARRY 32
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