在Scala 2.10中获取java.lang.Class [T]的Scala类型

问题描述

我正在查看 scala反射概述，想知道是否可以在Scala 2.10中将java.lang.Class<T>用作类型.

I was looking at the scala reflection overview and I'm wondering if it is possible to use a java.lang.Class<T> as a Type in Scala 2.10.

import scala.reflect.runtime.{ universe => ru }

class Reflector {
  def getType: ru.Type = {
    ru.typeOf[java.lang.String]
  }
  def getType[T](clazz: Class[T]): ru.Type = {
    //is it possible to implement me?
  }
}

是否可以在不更改其签名的情况下实现parse[T](clazz: Class[T]): ru.Type方法，以便能够使用new Reflector().parse(String.class)从Java调用它?

Is it possible to implement the parse[T](clazz: Class[T]): ru.Type method without changing its signature in order to be able to call it from java with new Reflector().parse(String.class)?

推荐答案

您可以像这样实现您的方法:

You could implement your method like this:

def getType[T](clazz: Class[T])(implicit runtimeMirror: ru.Mirror) =
  runtimeMirror.classSymbol(clazz).toType

然后这样称呼它:

implicit val mirror = ru.runtimeMirror(getClass.getClassLoader)
getType(classOf[String])

您可能会对镜像库感兴趣，因为它包含类似的方法

You might be interested in the smirror library as it contains a similar method

def sClassOf[T](clazz: Class[T])(implicit runtimeMirror: Mirror): SClass[T]

SClass包含typ属性的地方.

您可能希望将方法更改为此(将保留相同的签名)

You might want to change the method to this (that would keep the same signature)

def getType[T](clazz: Class[T]):ru.Type = {
  val runtimeMirror =  ru.runtimeMirror(clazz.getClassLoader)
  runtimeMirror.classSymbol(clazz).toType
}

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