如何生成FEN字符串并将其发送到Stockfish？

问题描述

我正在构建一个国际象棋GUI，应该与Stockfish对话。我听说我必须生成一个FEN字符串，以告知Stockfish已经采取的措施。所以问题是，我该怎么做？我在这里真的遇到了一个死胡同。我正在使用Eclipse IDE。

解决方案

我不确定您所做的工作或使用哪种编程语言，但是由于您使用的是Eclipse IDE，因此我m表示这是Java。

使Stockfish正常工作的热门提示是观看以下视频：

要解决您的问题：

那么，简单的解决方案就是寻找已经实施的项目ng FEN字符串。我知道他们很多。如果您想使用一种简单的笨拙的方式在Java中制作FEN字符串，我可以这样：

注意：实施过程相信您将整个开发板都放在了String [] []中（在这些晚点时间，我没麻烦让它变得更高级）

注意2：它不会构成整个FEN字符串。它缺少有效颜色，Castle可用性，En passant，Halfmove时钟和Fullmove编号，但是我敢肯定您将能够轻松实现该功能

输出：

  private final String RANK_SEPARATOR = /; 
 
 private String [] []公告板= {
 { r， n， b， q， k， b， n，  r}，
 { p， p， p， p， p， p， p， p}，
 { ，，，，，，，}，
 {，，，，，，， }，
 {，，，，，，，，}，
 {，，，， ，，，}，
 { P， P， P， P， P， P， P， P} ，
 { R， N， B， Q， K， B， N， R} 
}; 
 
 public String translateBoardToFEN（String [] [] board）{
 String fen =; 
 for（int rank = 0; rank< board.length; rank ++）{
 //计算空字段
 int empty = 0; 
 //每个级别为空字符串
字符串rankFen =; 
 for（int file = 0; file< board [rank] .length; file ++）{
 if（board [rank] [file] .length（）== 0）{
空++; 
} else {
 //如果不为零，则将数字加到fen中。 
 if（empty！= 0）rankFen + = empty; 
 //将字母添加到分
 rankFen + = board [rank] [file]; 
 //重置空
 empty = 0; 
} 
} 
 //如果不为零，则将数字加到分位数。 
 if（empty！= 0）rankFen + = empty; 
 //将等级加到分
 fen + = rankFen; 
 //添加等级分隔符。如果最后一个则加一个空格
 if（！（rank == board.length-1））{
 fen + = RANK_SEPARATOR; 
} else {
 fen + =; 
} 
} 
 return fen; 
} 
  

I am building a chess GUI, which is supposed to talk to Stockfish. I have heard that I have to generate a FEN-string, to tell Stockfish about the move that has been made. So the question is, how do I do this? I have really met a dead end here.. I am using the Eclipse IDE.

解决方案

I am not sure what you have done or in what programming language, but since you are using the Eclipse IDE, I'm suggesting it is Java.

A hot tips for making the Stockfish to work is by looking at this video:https://www.youtube.com/watch?list=PLQV5mozTHmacMeRzJCW_8K3qw2miYqd0c&v=vuvTFNreykk

The Stackoverflow linked in the video: Using the Universal Chess Interface

So to tackle your question:

Well, the simple solution would be to look for already implemented projects making FEN-strings. I know there are a lot of them. If you want a simple, yet clumsy way of making a FEN-string in Java I made you this:

Note: This implementation believes that you have your entire board in a String[][] (I didn't make the trouble making it more advanced at these late hours)

Note 2: It does not make the entire FEN-string. It is missing the Active color, Castling availability, En passant, Halfmove clock and the Fullmove number, but I'm sure you will be able to implement that easily

Output:

private final String RANK_SEPARATOR = "/";

private String[][] board = {
        {"r","n","b","q","k","b","n","r"},
        {"p","p","p","p","p","p","p","p"},
        {"","","","","","","",""},
        {"","","","","","","",""},
        {"","","","","","","",""},
        {"","","","","","","",""},
        {"P","P","P","P","P","P","P","P"},
        {"R","N","B","Q","K","B","N","R"}
};

public String translateBoardToFEN(String[][] board) {
    String fen = "";
    for (int rank = 0; rank < board.length; rank++) {
        // count empty fields
        int empty = 0;
        // empty string for each rank
        String rankFen = "";
        for (int file = 0; file < board[rank].length; file++) {
            if(board[rank][file].length() == 0) {
                empty++;
            } else {
                // add the number to the fen if not zero.
                if (empty != 0) rankFen += empty;
                // add the letter to the fen
                rankFen += board[rank][file];
                // reset the empty
                empty = 0;
            }
        }
        // add the number to the fen if not zero.
        if (empty != 0) rankFen += empty;
        // add the rank to the fen
        fen += rankFen;
        // add rank separator. If last then add a space
        if (!(rank == board.length-1)) {
            fen += RANK_SEPARATOR;
        } else {
            fen += " ";
        }
    }
    return fen;
}

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