如何以编程方式连接到 Android 中的特定 Wi-Fi 网络?

问题描述

我想设计一个应用，显示可用的 Wi-Fi 网络列表并连接到用户选择的任何网络.

I want to design an app which shows a list of Wi-Fi networks available and connect to whichever network is selected by the user.

我已经实现了显示扫描结果的部分.现在我想连接到用户从扫描结果列表中选择的特定网络.

I have implemented the part showing the scan results. Now I want to connect to a particular network selected by the user from the list of scan results.

我该怎么做?

推荐答案

您需要创建 WifiConfiguration 像这样的实例:

You need to create WifiConfiguration instance like this:

String networkSSID = "test";
String networkPass = "pass";

WifiConfiguration conf = new WifiConfiguration();
conf.SSID = """ + networkSSID + """;   // Please note the quotes. String should contain ssid in quotes

然后，对于 WEP 网络，您需要这样做:

Then, for WEP network you need to do this:

conf.wepKeys[0] = """ + networkPass + """;
conf.wepTxKeyIndex = 0;
conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);
conf.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.WEP40);

对于 WPA 网络，您需要像这样添加密码:

For WPA network you need to add passphrase like this:

conf.preSharedKey = """+ networkPass +""";

对于开放网络，您需要这样做:

For Open network you need to do this:

conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);

然后，您需要将其添加到 Android wifi 管理器设置中:

Then, you need to add it to Android wifi manager settings:

WifiManager wifiManager = (WifiManager)context.getSystemService(Context.WIFI_SERVICE);
wifiManager.addNetwork(conf);

最后，您可能需要启用它，以便 Android 连接到它:

And finally, you might need to enable it, so Android connects to it:

List<WifiConfiguration> list = wifiManager.getConfiguredNetworks();
for( WifiConfiguration i : list ) {
    if(i.SSID != null && i.SSID.equals(""" + networkSSID + """)) {
         wifiManager.disconnect();
         wifiManager.enableNetwork(i.networkId, true);
         wifiManager.reconnect();

         break;
    }
 }

UPD:在 WEP 的情况下，如果您的密码是十六进制的，则不需要用引号将其括起来.

UPD: In case of WEP, if your password is in hex, you do not need to surround it with quotes.

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