问题描述
我在表单上有一个树状视图，它包含数百个节点，其中许多是缩进的.例如，以资源管理器视图为例.声明:
int i = ExampleTreeView.GetNodeCount(true);
返回示例树视图中所有节点的计数.我尝试过搜索单线，但是如果树视图可以告诉您有多少个节点，是否有一种方法可以返回这些节点的扁平化"列表暨数组，也可以作为单线语句返回?
我已经看到了许多使用递归来构建扁平节点列表的示例，但是框架中可能有一些可以为我做的事情吗?我想认为该框架可能有一些功能，但是如果我必须使用递归进行操作，那就照做吧.
有谁知道框架中会为我做的事情吗?
I''ve got a treeview on a form and it contains a few hundred nodes, many indented. Think of the explorer view for example. This statement:
int i = ExampleTreeView.GetNodeCount(true);
returns the count of all the nodes in my example treeview. I''ve tried searching for a one-liner but if the treeview can tell you how many nodes there are, is there a method that will return a "flattened" list-cum-array of those nodes, also as one-liner statement?
I''ve seen lots of examples that use recursion to build a flattened list of nodes but maybe there''s something in the framework that''ll do it for me? I''d like to think the framework might have something but if I have to do it with recursion, then so be it.
Does anyone know of something builtin to the framework that''ll do that for me?
推荐答案
Root
branch1
leaf1
leaf2
branch2
leaf1
leaf2 默认的平面视图将只有四个元素，两个元素称为"leaf1"，两个元素称为"leaf2".
您将需要递归解析树.
A default flat view would have only four elements, two called "leaf1" and two called "leaf2".
You will have to recursively parse the tree.
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