C ++向量载体

本文介绍了C ++向量载体的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我想写一个程序，使用一个基类来定义一个算法来解决一个简单的问题。我使用一个ints的向量作为游戏板。我的问题是如何创建一个函数get_moves，返回一个游戏板的向量？I am trying to write a program that uses a base class to define an algorithm for solving a simple problem. I use a vector of ints as a 'game board'. My question is how can I create a function get_moves that returns a vector of game boards?这是我对函数的代码：std::vector< <std::vector<int> > takeaway::generateMoves( std::vector<int> currBoard ) { if( currBoard[0] == 1 || currBoard[0] == 2 ) { moves.push_back( 1 ); } else if( currBoard[0] == 3 ) { moves.push_back( 2 ); } else if( currBoard[0] == 4 ) { moves.push_back( 3 ); } else { moves.push_back( 1 ); moves.push_back( 2 ); moves.push_back( 3 ); } std::vector< <std::vector <int > > toReturn( moves ); for( int i = 0; i < moves.size(); i++ ) { std::cout << "MOVES: " << moves[i] << std::endl; } return toReturn;我得到的错误是： takeaway.cpp：55：error：模板参数1无效 takeaway.cpp：55：错误：模板参数2无效takeaway.cpp:55: error: template argument 1 is invalidtakeaway.cpp:55: error: template argument 2 is invalid如何正确创建和返回向量的向量？So my question is how can I properly create and return a vector of vectors?推荐答案您的模板声明中有太多的You have too many <'s on your template declarations.std::vector< std::vector<int> > takeaway::generateMoves( std::vector<int> currBoard ){ if( currBoard[0] == 1 || currBoard[0] == 2 ) { moves.push_back( 1 ); } else if( currBoard[0] == 3 ) { moves.push_back( 2 ); } else if( currBoard[0] == 4 ) { moves.push_back( 3 ); } else { moves.push_back( 1 ); moves.push_back( 2 ); moves.push_back( 3 ); } std::vector< std::vector<int> > toReturn; toReturn.push_back( moves ); for( int i = 0; i < moves.size(); i++ ) { std::cout << "MOVES: " << moves[i] << std::endl; } return toReturn;}可能有更多，但这是其中之一。There might be more, but that is one of them. 这篇关于C ++向量载体的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！