将std :: time_t转换为System :: DateTime的标准一致方式？

问题描述

我已经找到了一些有关将 std :: time_t 值转换为 System :: DateTime 和背部。然而，几乎所有的答案似乎都忽略了标准中实际上未定义的类型 std :: time_t 。大多数解决方案只需将 std :: time_t 转换为 std :: time_t 对象所需要的或应用算术运算可能是因为它是算术类型，但是没有关于这种操作的结果的规范。我知道大多数编译器将 time_t 定义为某种大小的 int ，但事实上它在许多实现中从 int32 更改为 int64 最近显示更改确实是可能的。

I have already found several answers related to converting a std::time_t value to System::DateTime and back. However, almost all answers seem to neglect that the type of std::time_t is actually undefined in the standard. Most solutions just cast std::time_t to whatever needed or apply arithmetic operations to a std::time_t object which is possible since it's an arithmetic type, but there is no specification about the result of such an operation. I know that most compilers define time_t as an int of some size but the fact alone that it has changed from int32 to int64 in many implementations recently shows that changes are indeed possible.

所以我想出了这个解决方案，这个应用程序应该使用任何类型的 std :: time_t code>。它从我所看到的工作。但我想知道 - 我可能不知道有什么可能的陷阱吗？

So I've come up with this solution which should work with any type of std::time_t. It works from what I have seen. But I was wondering - Are there any possible pitfalls I might be unaware of?

template <>
inline System::DateTime marshal_as(const std::time_t &from_object)
{
    // Returns DateTime in Local time format from time_t (assumed to be UTC)
    const auto unix_epoch = makeUtcTime(1970, 1, 1, 0, 0, 0);
    const auto unix_epoch_dt = System::DateTime(1970, 1, 1, 0, 0, 0, System::DateTimeKind::Utc);
    const auto secondsSinceEpoch = std::difftime(from_object, unix_epoch);
    return const_cast<System::DateTime&>(unix_epoch_dt).AddSeconds(secondsSinceEpoch).ToLocalTime();
} // end of System::DateTime marshal_as(const std::time_t &from_object)

template <>
inline std::time_t marshal_as(const System::DateTime &from_object)
{
    // Returns time_t in UTC format from DateTime
    auto from_dt = const_cast<System::DateTime&>(from_object).ToUniversalTime();
    return makeUtcTime(from_dt.Year, from_dt.Month, from_dt.Day, from_dt.Hour, from_dt.Minute, from_dt.Second);
} // end of std::time_t marshal_as(const System::DateTime &from_object)

3个假设：

• 结果 std :: time_t 应该是因为它不包含任何本地化信息


• 生成 System :: DateTime 应该是本地时间，因为 System :: DateTime :: Now 返回一个本地化的 DateTime


• makeUtcTime 是一个帮助函数，从提供的值创建一个 std :: tm 并创建一个UTC std :: time_t 出来。这是目前使用 _mkgmtime 实现的，因为我们的互操作代码可以安全地依赖于Microsoft扩展的存在。然而，UTC版本的 mktime 也可以在其他编译器中使用（标准 mktime 期望本地时间）。

• Resulting std::time_t should be in UTC since it doesn't contain any info on localization
• Resulting System::DateTime should be local time since System::DateTime::Now returns a localized DateTime
• makeUtcTime is a helper function creating a std::tm from the values supplied and creates a UTC std::time_t out of it. This is currently implemented using _mkgmtime because our interop code can safely rely on the existence of Microsoft extensions. However, a UTC version of mktime is readily available in other compilers as well (standard mktime expects local time).

两个不太重要的事情要考虑：

2 less important things to consider:

• const_cast 是必要的，因为marshal_as-template需要一个 const T& 作为参数，我无法访问一个const .NET值类型对象的属性。但是可能会有更好的解决方案。


• 如果 unix_epoch ... 的东西应该是 static const ？
• 
  

• The const_cast is necessary because the marshal_as-template expects a const T& as parameter and I can't access the properties of a const .NET value-type object. However there might be a better solution.
• Should the unix_epoch... stuff be static const?

（我不知道这是否应该发布在程序员交换上，因为它是一个更多的讨论，但由于它是一个非常具体的C ++问题我认为这可能是更好的地方）

(I wasn't sure if this should be posted on "Programmers Exchange" since it's more of a discussion but since it's a very specific C++ question I thought SO might be the better place to ask)

推荐答案

坚持标准一致的方式进行这种转换。 std :: time_t和System :: DateTime唯一会遇到的地方是由。其中有一个现在，肯定会是，只有一个实现。 Mono项目可能被认为是另一个项目的最有可能的来源，但现在他们完全不感兴趣提供混合模式实现，这是您考虑使用C ++ / CLI的唯一原因。

It just isn't very productive to insist on a "standard conformant" way to make this conversion. The only place where an std::time_t and a System::DateTime are ever going to meet is covered by the Ecma-372 standard. Of which there is right now, and surely will ever be, only one implementation. The Mono project could be assumed to be the most likely source of another one, but right now they appear entirely uninterested in providing a mixed-mode implementation, the only reason you'd ever consider using C++/CLI.

std :: time_t正在稳步前进到Y2K38灾难。由于微软先前已经做了一些事情，而且真的要这样做，因为他们去了LLP64，但是所有人都指望他们的，使他们摆脱困境。换句话说，2038年还没有剩余的32位处理器仍然运行。这可能是一个自我实现的预言。

std::time_t is steadily marching towards the Y2K38 disaster. With Microsoft pre-emptively having done something about it, and really having to do so because they went for LLP64, but everybody else counting on their LP64 data model keeping them out of trouble. In other words, no remaining 32-bit processors still running in 2038. This could well be a self-fulfilling prophesy.

无论如何，转换将要工作自1970年1月1日以来经过毫秒。这可以是32位或64位积分值，具体取决于实现。对于System :: DateTime，使用毫秒需要使用 double 。并且任何编译器将能够在双精度值和整数值之间进行转换，它是大括号语言中的标准转换。具有毫秒精度的转换，直到DateTime :: MaxValue。此外，。至少在2038年之前，你不会有移植这个代码的问题：

Regardless, the conversion is going to have to work with elapsed milliseconds since 1/1/1970. And that can be a 32-bit or a 64-bit integral value, depending on implementation. For System::DateTime, working with milliseconds requires using double. And any compiler is going to be able to convert between double and an integral value, it is a standard conversion in the curly brace languages. A conversion that has millisecond accuracy all the way up to DateTime::MaxValue. One that furthermore is guaranteed to round-trip. You are not going to have a problem ever porting this code, at least until 2038:

#include <ctime>

using namespace System;

public ref class Conversions {
public:
    static DateTime time_t2DateTime(std::time_t date) {
        double msec = static_cast<double>(date);
        return DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind::Utc).AddMilliseconds(msec);

    }
    static std::time_t DateTime2time_t(DateTime date) {
        TimeSpan diff = date.ToUniversalTime() - DateTime(1970, 1, 1);
        return static_cast<std::time_t>(diff.TotalMilliseconds);

    }
};

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