问题描述
我有两个集合 user
和 Type
.我希望显示标记为 IsPreffered = TRUE
的电子邮件 ID,我需要将 email.Type 映射到 Type.ID
{ "user" : [
{
"Name" : "B. Balamanigandan",
"Email": [
{
"Id": "[email protected]",
"IsPreffered": true,
"Type": 1,
},
{
"Id": "[email protected]",
"IsPreffered": false,
"Type": 2,
}
]}
]};
{
"Type": [
{
"ID": 1,
"Name": "Private"
},
{
"ID": 2,
"Name": "Home"
},
{
"ID": 3,
"Name": "Business"
},
]}
HTML 源代码:
<span ng-repeat="email in collection.user[0].Email | filter: {IsPreffered : true} " ng-if="$last"> {{email.Id}}</span>
这里我需要为上述 HTML 指定类型私人".如何将 user[0].Email.Type
映射到 Type.ID
并获取适当的 >Type.Name
Here I need to Specify the Type "Private" for the above HTML. How to Map the user[0].Email.Type
to Type.ID
and fetch the appropriate Type.Name
请使用 HTML 级别而非 JavaScript 级别过滤条件.请帮助我.
Kindly filter the condition using HTML Level not in JavaScript Level. Kindly assist me.
推荐答案
我建议用代码而不是标记来做,但如果你需要这是一种映射到类型的方法:
I would suggest doing it in code rather than the markup, but if you need this is one way you can map to Type:
<span
ng-repeat="email in collection.user[0].Email| filter: {IsPreffered : true} "
ng-if="$last">
Email : {{email.Id}} ,
<span ng-repeat="typename in typeCollection.Type|filter:{ID : email.Type}">
Type: {{typename.Name}}
</span>
</span>
typeCollection 在哪里:
where typeCollection is :
$scope.typeCollection = {
"Type": [{
"ID": 1,
"Name": "Private"
}, {
"ID": 2,
"Name": "Home"
}, {
"ID": 3,
"Name": "Business"
}, ]
};
请注意,您需要在标记中再添加一个 ng-repeat,因为过滤器适用于数组.
Please note that you needed one more ng-repeat in markup because filter works on an array.
您也可以使用 ng-init 执行此操作:
You can also do this using ng-init:
<span
ng-repeat="email in collection.user[0].Email| filter: {IsPreffered : true} "
ng-if="$last">
Email : {{email.Id}} ,
<span ng-init="types = (typeCollection.Type|filter:{ID : email.Type})">
Type: {{types[0].Name}}
</span>
</span>
这篇关于使用 AngularJS HTML 映射两个集合(内部连接)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!