本文介绍了基于属性排序和分组XML的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我使用LINQ在C#中的工作,以XML和我需要做对我的XML节点的属性部分的排序。我的XML看起来是这样的。

I am working with LINQ to XML in C# and I need to do some sorting on the attributes of my xml nodes. My xml looks something like this.

<root>
    <Claim key="1" carrier="carA" zip="34343" pages="1"/>
    <Claim key="2" carrier="carA" zip="34343" pages="2"/>
    <Claim key="3" carrier="carB" zip="34343" pages="4"/>
</root>

我可以使用排序依据子句中的XML进行排序,如

I can sort the xml using the orderby clause such as

 var query= from claim in root.Elements("Claim")
            let Key = claim.Attributes("Key").First().Value
            let Carrier = claim.Attributes("Carrier").First().Value
            let CarrierZip = int.Parse(claim.Attributes("CarrierZip").First().Value)
            let Pages = claim.Attributes("Pages").First().Value
            orderby Pages ascending, CarrierZip ascending, Carrier ascending
            select claim;

然后,我得到的查询键列表。

Then I get a list of the keys from query.

我想要做的就是让所有的债权集合1页,然后全部用2页等等说法,但我不知道是什么的最大页数即可。

What I want to do is get collections of all the claims with 1 page, then all the claims with 2 pages and so on, but I do not know what the maximum number of pages can be.

谁能帮助我?

编辑 -

我改变了我的intial思考如何做到这一点,我现在想提出类似于此的了。

I changed my intial thought on how to accomplish this and I now would like the out put to resemble this.

List<List<List<List<int>>>>

All claims
- 1 page
   -zip1
      -carr1
         -int claim key
         -int claim2 key
      - car2
   -zip2
      -car1
- 2 pages
   -zip1

等。诀窍是我需要查询的节点,并得到多个团体出来。可在我的发言这样做或者是一系列所需的报表?

and so on. The trick is I need to query the nodes and get multiple groups out of it. Can this be done in my statement or is a series of statements required?

推荐答案

您只需要添加一个 GROUPBY 子句:

You just need to add a GroupBy clause:

var query= from claim in root.Elements("Claim")
           let Key = claim.Attributes("Key").First().Value
           let Carrier = claim.Attributes("Carrier").First().Value
           let CarrierZip = int.Parse(claim.Attributes("CarrierZip").First().Value)
           let Pages = claim.Attributes("Pages").First().Value
           orderby Pages ascending, CarrierZip ascending, Carrier ascending
           group new { CarrierZip, Carrier, Key } by Pages;

foreach (var group in query)
{
    Console.WriteLine("Claims with {0} pages:", group.Key);
    foreach (var entry in group)
    {
        Console.WriteLine("  {0} {1} {2}", entry.CarrierZip, entry.Carrier,
                          entry.Key);
    }
}

编辑:要获得名单,其中,名单,其中,INT&GT;&GT; 此,你会使用:

var claims = query.Select(group => group.Select(x => x.Key).ToList())
                  .ToList();

另外,如果你不需要CarrierZip和运营商的结果,可以简化查询和listifying为:

Alternatively, if you don't need the CarrierZip and Carrier in the results, you can simplify the query and the listifying to:

var query= from claim in root.Elements("Claim")
           let Key = claim.Attributes("Key").First().Value
           let Carrier = claim.Attributes("Carrier").First().Value
           let CarrierZip = int.Parse(claim.Attributes("CarrierZip").First().Value)
           let Pages = claim.Attributes("Pages").First().Value
           orderby Pages ascending, CarrierZip ascending, Carrier ascending
           group Key by Pages;

var claims = query.Select(group => group.ToList())
                  .ToList();

这篇关于基于属性排序和分组XML的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-27 22:49