问题描述
无论我尝试插入什么数据,我似乎都会在每次插入时收到下面列出的错误.所以也许我的桌子坏了还是什么?无论如何,这是我的问题:
I seem to get the error listed below on every insert no matter what data I try to insert. So maybe my table was corrupted or something? Anyway, here's my question:
我有一个MySQL表
CREATE TABLE `AcpConfig` (
`ndss_id` int(11) NOT NULL default '0',
`acp_id` int(11) NOT NULL default '0',
`run_date` date NOT NULL default '0000-00-00',
`hw_5_threshold` tinyint(1) NOT NULL default '0',
`stp_on` tinyint(1) NOT NULL default '0',
`sort_on` tinyint(1) NOT NULL default '0',
`afcs_ocr_message_format` tinyint(1) NOT NULL default '0',
`use_hw` tinyint(1) NOT NULL default '0',
`test_mode` tinyint(1) NOT NULL default '0',
`afcs_version` varchar(255) NOT NULL default '',
`acp_build` varchar(255) NOT NULL default '',
`id` int(11) NOT NULL auto_increment,
`swstp_in_acp_rack` int(11) NOT NULL default '0',
`acplookup_id` int(11) NOT NULL default '0',
`bfind_cksum` varchar(255) NOT NULL default '',
`tz_cksum` varchar(255) NOT NULL default '',
`fetched` varchar(4) NOT NULL default '"NO"',
PRIMARY KEY (`id`),
UNIQUE KEY `ndss_id` (`ndss_id`,`acp_id`,`run_date`),
KEY `ndss_acp` (`ndss_id`,`acp_id`),
KEY `ndss_acp_rundate` (`ndss_id`,`acp_id`,`run_date`),
KEY `run_date` (`run_date`),
KEY `acplookup_rundate` (`acplookup_id`,`run_date`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1
它大约有50万行.我正在尝试执行一个简单的INSERT
And it's got about half a million rows. I'm trying to perform a simple INSERT
INSERT INTO AcpConfig (ndss_id, acp_id, run_date, hw_5_threshold, stp_on, sort_on, afcs_ocr_message_format, use_hw, test_mode, afcs_version, acp_build, swstp_in_acp_rack, acplookup_id, bfind_cksum, tz_cksum) VALUES ('75', '5', '2009-07-22', '75', '1', '1', '0', '1', '0', '1.5.2', '041709', '2', '269', '0', '1950359846');
它给了我错误
ERROR 1062 (23000): Duplicate entry '502831' for key 1
表示我违反了对ndss_id,acp_id和run_date这三个字段的唯一约束. (ID 502831不是我的表中的行,并且似乎是如果已插入该行时将使用的下一个ID.)问题是,如果我针对具有相同值的那些字段进行选择
which implies that I'm violating my UNIQUE constraint on the three fields ndss_id, acp_id, and run_date. (The id 502831 is not a row in my table and seems to be the next id that would be used if the row had been inserted.) The problem is, if I SELECT against those fields with the same values
select * from AcpConfig where ndss_id=75 and acp_id=5 and run_date='2009-07-22';
然后不返回任何结果.因此,我实际上并没有复制任何内容.我的其他键只是索引,而不是唯一约束.正如我从CREATE TABLE语句中看到的那样,我还有一个UNIQUE约束.那为什么告诉我我有重复的东西?
then it returns no results. So I'm not actually duplicating anything. My other keys are all just indexes and not unique constraints; I also have the one UNIQUE constraint as you can see from my CREATE TABLE statement. So why is it telling me that I have a duplicate?
推荐答案
显然该表已损坏.我运行CHECK TABLE
并看到一些损坏错误,然后运行REPAIR TABLE
,它似乎可以正常工作.之后我的INSERTS又开始工作了.
Apparently the table was corrupted. I ran CHECK TABLE
and saw some corruption errors and then ran REPAIR TABLE
and it seemed to work; afterward my INSERTS started working again.
mysql> check table AcpConfig;
+---------------+-------+----------+----------------------------------------------------------+
| Table | Op | Msg_type | Msg_text |
+---------------+-------+----------+----------------------------------------------------------+
| acp.AcpConfig | check | warning | 8 clients are using or havent closed the table properly |
| acp.AcpConfig | check | warning | Size of datafile is: 32079848 Should be: 32079784 |
| acp.AcpConfig | check | error | Found 495762 keys of 495761 |
| acp.AcpConfig | check | error | Corrupt |
+---------------+-------+----------+----------------------------------------------------------+
4 rows in set (3.50 sec)
mysql> repair table AcpConfig;
+---------------+--------+----------+----------------------------------------------+
| Table | Op | Msg_type | Msg_text |
+---------------+--------+----------+----------------------------------------------+
| acp.AcpConfig | repair | warning | Number of rows changed from 495761 to 495762 |
| acp.AcpConfig | repair | status | OK |
+---------------+--------+----------+----------------------------------------------+
2 rows in set (13.14 sec)
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