数据库错误发生错误编号：1062

问题描述

我试图使选项更新三表一个执行我的CI与sql那里，但为什么它的仍然是错误？

这是错误警告：

 发生数据库错误
 
错误号码：1062 
 
键1的重复条目'0'
 
 UPDATE`t_publisher` SET`id_publisher` = NULL，`publisher` = NULL，`artis` = NULL，`id_label` = NULL WHERE`id_publisher `='113'
  

这是代码：

 函数更新（$ id_user = null）
 {
 if（（$ this-> input-> post （'submit'）=='Update'））{
 $ user = $ this-> input-> post（'username'）; 
 $ pass = $ this-> input-> post（'userpassword'）; 
 $ ussta = $ this-> input-> post（'userstatus'）; 
 $ usty = $ this-> input-> post（'usertype'）; 
 
 $ data = array（
'user_name'=> $ user，
'user_pass'=> $ pass，
'user_status'=> $ ussta，
'user_type'=> $ usty）; 
 
 $ this-> db-> where（'user_id'，$ this-> input-> post（'id'），$ data）; 
 $ this-> db-> update（t_user，$ data）; 
 
 $ data1 = array（
'id_publisher'=> $ id_publis，
'publisher'=> $ publis，
'artis'=> $ ar，
'id_label'=> $ id_lab）; 
 
 $ this-> db-> where（'id_publisher'，$ this-> input-> post（'id'），$ data）; 
 $ this-> db-> update（t_publisher，$ data1）; 
 echo $ this-> db-> last_query（）; 
 die（）; 
 
 $ data2 = array（
'id_label'=> $ id_lab，
'label'=> $ label）; 
 
 $ this-> db-> where（'id_label'，$ this-> input-> post（'id'），$ data）; 
 $ this-> db-> update（t_label，$ data2）; 
 echo $ this-> db-> last_query（）; 
 die（）; 
 redirect（registrasi / reg）; 
} 
 $ var ['data'] = $ this-> db-> query（select * from t_user where USER_ID ='$ id_user'） - > row_array 
 $ var1 ['data'] = $ this-> db-> query（select * from t_publisher where id_publisher ='$ id_publis'） - > row_array（）; 
 $ var2 ['data'] = $ this-> db-> query（select * from t_label where id_label ='$ id_lab'） - > row_array 
 $ this-> load-> view（'update'，$ var，$ var1，$ var2） 
} 
  

我的代码有什么问题？请帮忙。感谢。

解决方案

您的 UPDATE $ c> id_publisher 列到 NULL ，并根据列的名称和您收到的错误， / em>列是表的 PRIMARY KEY ，设置为无符号NOT NULL 。

$ b $因为这样，当你做 id_publisher = NULL 时，MySQL会将其转换为 id_publisher = 0 由于 unsigned 部分。这将在第一次执行时执行，但是当您在第二列执行时，您将尝试插入 主键值 0 ，这是不允许的。

根据您的示例中 die（）语句的位置代码，我假设以下块是罪魁祸首：

  $ data1 = array（
'id_publisher' > $ id_publis，
'publisher'=> $ publis，
'artis'=> $ ar，
'id_label'=> $ id_lab）; 
 
 $ this-> db-> where（'id_publisher'，$ this-> input-> post（'id'），$ data）; 
 $ this-> db-> update（t_publisher，$ data1）; 
  

这里， $ id_publis 空或空。

我建议从 id_publisher = NULL > UPDATE 子句，就像删除'id_publisher'=>数组中的$ id_publis，，或重新思考你实际需要将其设置为 null 开始（在这种情况下，会删除该行更有益吗？）

i tried to make option update three table with one execution for my CI with sql there, but why its still error?

this is the error warning:

A Database Error Occurred

Error Number: 1062

Duplicate entry '0' for key 1

UPDATE `t_publisher` SET `id_publisher` = NULL, `publisher` = NULL, `artis` = NULL, `id_label` = NULL WHERE `id_publisher` = '113'

this is the code:

function update($id_user=null)
  {
   if (($this->input->post('submit') == 'Update')){
    $user=$this->input->post('username');
    $pass=$this->input->post('userpassword');
    $ussta=$this->input->post('userstatus');
    $usty=$this->input->post('usertype');

   $data = array(
    'user_name' => $user,
    'user_pass' => $pass,
    'user_status' => $ussta,
    'user_type' => $usty);

    $this->db->where('user_id', $this->input->post('id'), $data);
    $this->db->update("t_user",$data);

   $data1 = array(
    'id_publisher' => $id_publis,
    'publisher' => $publis,
    'artis' => $ar,
    'id_label' => $id_lab);

    $this->db->where('id_publisher', $this->input->post('id'), $data);
    $this->db->update("t_publisher",$data1);
    echo $this->db->last_query();
    die();

   $data2 = array(
    'id_label' => $id_lab,
    'label' => $label);

    $this->db->where('id_label', $this->input->post('id'), $data);
    $this->db->update("t_label",$data2);
    echo $this->db->last_query();
    die();
    redirect("registrasi/reg");
   }
    $var['data'] = $this->db->query("select * from t_user where USER_ID= '$id_user'")->row_array();
    $var1['data'] = $this->db->query("select * from t_publisher where id_publisher = '$id_publis'")->row_array();
    $var2['data'] = $this->db->query("select * from t_label where id_label = '$id_lab'")->row_array();
    $this->load->view('update', $var,$var1,$var2);
}

whats wrong with my code? please help. thanks before.

解决方案

Your UPDATE clause is setting the id_publisher column to NULL, and, based on the name of the column and the error you're receiving, that column is the table's PRIMARY KEY with a setting of unsigned NOT NULL.

Because of this, when you do id_publisher = NULL, MySQL converts it to id_publisher = 0 due to the unsigned part. This will execute fine the first time, however, when you run it on a second row you will now be attempting to insert a second primary-key value of 0, which is not allowed.

Based on the location of the die() statement in your sample code, I'm assuming the following block is the culprit:

   $data1 = array(
    'id_publisher' => $id_publis,
    'publisher' => $publis,
    'artis' => $ar,
    'id_label' => $id_lab);

    $this->db->where('id_publisher', $this->input->post('id'), $data);
    $this->db->update("t_publisher",$data1);

Here, your $id_publis variable is either empty or null.

I would suggest to either remove the id_publisher = NULL portion from the UPDATE clause which is as simple as removing 'id_publisher' => $id_publis, from the $data1 array, or rethink the reason you actually need to set it to null to begin with (in this case, would deleting the row be more beneficial?)

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