如何将元组元素作为参数传递给函数?

问题描述

我有一个由元组组成的列表，我想将每个元组的元素作为参数传递给函数:

I have a list consisting of tuples, I want to pass each tuple's elements to a function as arguments:

mylist = [(a, b), (c, d), (e, f)]

myfunc(a, b)
myfunc(c, d)
myfunc(e, f)

我该怎么做?

推荐答案

实际上，这在Python中非常简单，只需遍历列表并使用splat运算符(*)即可将元组解压缩为功能:

This is actually very simple to do in Python, simply loop over the list and use the splat operator (*) to unpack the tuple as arguments for the function:

mylist = [(a, b), (c, d), (e, f)]
for args in mylist:
    myfunc(*args)

例如:

>>> numbers = [(1, 2), (3, 4), (5, 6)]
>>> for args in numbers:
...     print(*args)
...
1 2
3 4
5 6

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