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问题描述
我有基于此类的视图:
class Browse(APIView):
'''
Browse associations
'''
permission_classes = [TokenHasReadWriteScope]
def get(self,request,format=None):
reply={}
status=200
try:
filter_options={}
name=request.query_params.get('name','').strip()
if name:
filter_options['name__icontains']=name
associations=Association.objects.filter(**filter_options)values('id','name')
page=request.query_params.get('page',1)
paginator=Paginator(associations,20)
data=paginator.page(page)
except PageNotAnInteger:
data=paginator.page(1)
except EmptyPage:
data=paginator.page(paginator.num_pages)
except:
status=400
reply['detail']=(_('ErrorProcessingRequest'))
if status==200:
reply['associations']=list(data)
reply['total_num_of_pages']=paginator.num_pages
reply['total_rows_found']=paginator.count
return JsonResponse(reply,status=status)
现在,我有另一个面向内部用户的应用程序(不同的登录名和所有用户名),但我仍要列出关联.上面的代码很短,我不介意将其粘贴到那里,只是想知道是否可以通过调用另一个应用程序的views.py中的Browse来避免DRY.
Now I have another app that is oriented towards internal users (different login and all) but I want to list the associations still. The above code is short and i don't mind pasting it there but just wondering if I can avoid DRY by calling the Browse from views.py of another app.
当前,我尝试从应用2中进行尝试:
Currently, I trie this from app 2:
from app1.views import Browse
b=Browse()
#but I cant serialize it as it returns <app1.views.Browse object at 0x0000000006CE0E80> is not JSON serializable
推荐答案
按照以下.我要做的就是:
Solved it following this SO Answer. All I had to do was:
view = Browse.as_view()
return view(request)
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