问题描述
我打算在MCMC例程中使用Boost odeint库来估计ODE模型中的参数。由于这些ODE可能是刚性的,我需要能够将雅可比传递到带有导数的求解器中。我想创建一个类,其参数和初始值作为私有成员,然后导数,jacobian和方法更改参数作为公共方法。我试图修改僵硬的例子从odeint网站使用一个类包含两者,但我收到错误错误:没有匹配的函数调用'Fitzhugh :: deriv()'时,在复制。我不是一个有经验的C ++程序员,所以这可能是一个概念上的错误。这是代码。
I intend to use the Boost odeint library in an MCMC routine to estimate parameters in an ODE model. Since these ODEs may be stiff, I need to be able to pass the jacobian into the solver with the derivative. I would like to make a class which has the parameters and initial values as private members and then the derivative, jacobian, and methods to change the parameters as public methods. I tried to modify the stiff example from the odeint website to use one class containing both, but am receiving the error 'error: no matching function for call to 'Fitzhugh::deriv()' when comiling. I am not an experienced C++ programmer, so this is likely a conceptual mistake. Here is the code.
/* Fitzhugh Nagumo Equation in odeint */
#include <iostream>
#include <fstream>
#include <utility>
#include <cmath>
#include <boost/numeric/odeint.hpp>
#include <boost/phoenix/core.hpp>
#include <boost/phoenix/operator.hpp>
using namespace std;
using namespace boost::numeric::odeint;
namespace phoenix = boost::phoenix;
//[ stiff_system_definition
typedef boost::numeric::ublas::vector< double > vector_type;
typedef boost::numeric::ublas::matrix< double > matrix_type;
class Fitzhugh
{
private:
double a;
double b;
double c;
public:
Fitzhugh( double a_, double b_, double c_ ) : a(a_), b(b_), c(c_) { }
void deriv ( const vector_type &x , vector_type &dxdt , double )
{
dxdt[ 0 ] = c*(x[0] - pow(x[0], 3.0)/3.0 + x[1]);
dxdt[ 1 ] = -(x[0] - a + b*x[1])/c;
}
void jac ( const vector_type &x, matrix_type &J , const double & , vector_type &dfdt )
{
J( 0 , 0 ) = c*(1 - pow(x[0], 2.0));
J( 0 , 1 ) = c;
J( 1 , 0 ) = -1/c;
J( 1 , 1 ) = -b/c;
dfdt[0] = 0.0;
dfdt[1] = 0.0;
}
};
int main( int argc , char **argv )
{
// typedef rosenbrock4< double > stepper_type;
// typedef rosenbrock4_controller< stepper_type > controlled_stepper_type;
// typedef rosenbrock4_dense_output< controlled_stepper_type > dense_output_type;
//[ integrate_stiff_system
vector_type x( 2 , 1.0 );
Fitzhugh fitzhugh(0.2, 0.2, 3.0);
size_t num_of_steps = integrate_const( make_dense_output< rosenbrock4< double > >( 1.0e-6 , 1.0e-6 ) ,
make_pair( fitzhugh.deriv() , fitzhugh.jac() ) ,
x , 0.0 , 50.0 , 0.01 ,
cout << phoenix::arg_names::arg2 << " " << phoenix::arg_names::arg1[0] << "\n" );
//]
clog << num_of_steps << endl;
return 0;
}
以下是完整输出
/home/chris/C++/examples/fitzhugh/main.cpp: In function ‘int main(int, char**)’:
/home/chris/C++/examples/fitzhugh/main.cpp:60:39: error: no matching function for call to ‘Fitzhugh::deriv()’
/home/chris/C++/examples/fitzhugh/main.cpp:60:39: note: candidate is:
/home/chris/C++/examples/fitzhugh/main.cpp:30:14: note: void Fitzhugh::deriv(const vector_type&, vector_type&, double)
/home/chris/C++/examples/fitzhugh/main.cpp:30:14: note: candidate expects 3 arguments, 0 provided
/home/chris/C++/examples/fitzhugh/main.cpp:60:56: error: no matching function for call to ‘Fitzhugh::jac()’
/home/chris/C++/examples/fitzhugh/main.cpp:60:56: note: candidate is:
/home/chris/C++/examples/fitzhugh/main.cpp:36:14: note: void Fitzhugh::jac(const vector_type&, matrix_type&, const double&, vector_type&)
/home/chris/C++/examples/fitzhugh/main.cpp:36:14: note: candidate expects 4 arguments, 0 provided
推荐答案
传递成员函数需要使用绑定机制。如果你有一个c ++ 11编译器,你可以使用std :: bind;包括std :: placeholder命名空间:使用命名空间std :: placeholder;
然后使用std :: bind从< functional>
:
to pass member function you need to use a bind mechanism. if you have a c++11 compiler you can use std::bind; include the std::placeholders namespace: using namespace std::placeholders;
then use std::bind from <functional>
:
make_pair(bind(& Fitzhugh :: deriv,& fitzhugh,_1,_2,_3),
bind(& Fitzhugh :: jac,& fitzhugh,_1,_2,_3,_4))
这篇关于Boost odeint类与派生和jacobian的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!