numpy:将数组转换为三角矩阵 | 将数组转换为三角矩阵

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问题描述

我正在寻找一种将线性数组转换为三角矩阵的内置方法.当我找不到一个时，我正在寻求实施一个的帮助.

I was looking for a built in method to convert an linear array to triangular matrix. As I failed in find one I am asking for help in implementing one.

想象一个像这样的数组:

Imagine an array like:

In [203]: dm
Out[203]: array([ 0.80487805,  0.90243902,  0.85365854, ...,  0.95121951,
                  0.90243902,  1.        ])

In [204]: dm.shape
Out[204]: (2211,)

我想将此数组转换为三角形矩阵或对称矩形矩阵.

And I would like to convert this array to a an triangular matrix or a symmetric rectangular matrix.

 In [205]: reshapedDm = dm.trian_reshape(67, 67)

我如何实现trian_reshape作为从一维数组返回三角矩阵的函数?

How I would implement trian_reshape as function that returns an triangular matrix from 1-D array?

推荐答案

>>> tri = np.zeros((67, 67))
>>> tri[np.triu_indices(67, 1)] = dm

有关详细信息，请参见文档以获取triu_indices .要获取低三角矩阵，请使用np.tril_indices并将偏移量设置为-1而不是1.

See doc for triu_indices for details. To get a lower-triangular matrix, use np.tril_indices and set the offset to -1 instead of 1.

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