本文介绍了如何基于属性合并数组中的对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试合并一个数组中的重复对象,同时添加一些属性值并将属性连接到一个数组中,但是我被卡住了。
I am trying to merge recurring object within an array while adding some of their attributes value and concatenating on attribute into an array, but I am stuck.
这是我正在处理的数组类型:
Here's the kind of array I am processing :
[{
"Favorites": 0,
"Frequency": 1,
"Hashtag": "19h30",
"Replies": 0,
"Retweets": 1,
"tweetId": 615850479952785400
}, {
"Favorites": 0,
"Frequency": 1,
"Hashtag": "80s",
"Replies": 0,
"Retweets": 1,
"tweetId": 617319253738393600
}, {
"Favorites": 0,
"Frequency": 1,
"Hashtag": "80s",
"Replies": 0,
"Retweets": 1,
"tweetId": 616521677275533300
}, {
"Favorites": 1,
"Frequency": 1,
"Hashtag": "AloeBlacc",
"Replies": 0,
"Retweets": 1,
"tweetId": 617309488572420100
}, {
"Favorites": 2,
"Frequency": 1,
"Hashtag": "Alpes",
"Replies": 0,
"Retweets": 1,
"tweetId": 615481266348146700
}]
我希望找到最终结果:
[{
"Favorites": 0,
"Frequency": 1,
"Hashtag": "19h30",
"Replies": 0,
"Retweets": 1,
"tweetId": 615850479952785400
}{
"Favorites": 0,
"Frequency": 2,
"Hashtag": "80s",
"Replies": 0,
"Retweets": 2,
"tweetId": [617319253738393600 ,
616521677275533300]
}, {
"Favorites": 1,
"Frequency": 0,
"Hashtag": "AloeBlacc",
"Replies": 0,
"Retweets": 1,
"tweetId": 617309488572420100
}, {
"Favorites": 2,
"Frequency": 0,
"Hashtag": "Alpes",
"Replies": 0,
"Retweets": 1,
"tweetId": 615481266348146700
}]
目前,我尝试在循环中循环但没有成功,我被卡住了。
For the moment, I tried looping within a loop but with no success and I am stuck.
var mergedHashtags = [];
var merged={};
for (var i = 0; i < hashtags.length-1; i++) {
var a = hashtags[i];
// start second loop at next element in array
for (var j = i+1; j < hashtags.length; j++) {
var b = hashtags[j];
console.log('a',a,'b',b, 'i',i,'j',j);
if (a.Hashtag===b.Hashtag) {
var tIds = [a.tweetId];
merged.Hashtag = a.Hashtag;
merged.tweetId = tIds.concat(b.tweetId);
merged.Favorites = a.Favorites+b.Favorites;
merged.Retweets = a.Retweets+b.Retweets;
merged.Replies = a.Replies+b.Replies;
merged.Frequency = a.Frequency+b.Frequency;
mergedHashtags.push(merged);
console.log('same', merged);
continue;
}else{
mergedHashtags.push(a);
i=j-1;
console.log('diff',a);
break;
}
}
}
感谢您的帮助很多!
提前致谢
Q。
Thanks in advanceQ.
推荐答案
您可以创建临时存储对象
并按 Hashtag
存储项目,这样您就不必再循环查找是否存在具有相同标签的项目
。
You can create a temp store object
and store items by its Hashtag
, so you don't have to loop again to find if there exist the item with same Hashtag
.
var merge = function(list) {
var result = [];
var store = {};
var addables = ['Favorites', 'Retweets', 'Replies', 'Frequency'];
list.forEach(function(item) {
// Check exist by hashtag.
if (typeof store[item.Hashtag] === 'undefined') {
// clone item, not alter origin list.
store[item.Hashtag] = JSON.parse(JSON.stringify(item));
result.push(store[item.Hashtag]);
} else {
var soruce = store[item.Hashtag];
// Check if its already combined or not.
if( Object.prototype.toString.call(soruce.tweetId) === '[object Array]') {
soruce.tweetId.push(item.tweetId);
} else {
soruce.tweetId = [soruce.tweetId, item.tweetId];
}
// Add addable attributes.
addables.forEach(function(key) {
soruce[key] += item[key];
});
}
});
return result;
};
var list = [{
"Favorites": 0,
"Frequency": 1,
"Hashtag": "19h30",
"Replies": 0,
"Retweets": 1,
"tweetId": 615850479952785400
}, {
"Favorites": 0,
"Frequency": 1,
"Hashtag": "80s",
"Replies": 0,
"Retweets": 1,
"tweetId": 617319253738393600
}, {
"Favorites": 0,
"Frequency": 1,
"Hashtag": "80s",
"Replies": 0,
"Retweets": 1,
"tweetId": 616521677275533300
}, {
"Favorites": 1,
"Frequency": 1,
"Hashtag": "AloeBlacc",
"Replies": 0,
"Retweets": 1,
"tweetId": 617309488572420100
}, {
"Favorites": 2,
"Frequency": 1,
"Hashtag": "Alpes",
"Replies": 0,
"Retweets": 1,
"tweetId": 615481266348146700
}];
console.log(merge(list));
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