问题描述
为什么不迭代?
import logging
logging.basicConfig(level=logging.DEBUG)
x = []
y = [[] for n in range(0, 1)]
linedata = ["0","1","2"]
x.append( linedata[0] )
d = linedata[1:]
logging.debug( "d: {}".format(d) )
e = enumerate(d)
logging.debug( list(e) )
for k, v in e:
logging.debug( "k:{} v:{}".format( k, v ) )
y[int(k)].append( v )
#for d in [(0,1)]:
#logging.debug( "k:{} v:{}".format( d[0], d[1] ) )
#y[d[0]].append( d[1] )
logging.debug( x )
logging.debug( y )
输出:
DEBUG:root:d: ['1', '2']
DEBUG:root:[(0, '1'), (1, '2')]
DEBUG:root:['0']
DEBUG:root:[[]]
文件:
- https://docs.python.org/3/reference/compound_stmts.html#for
- https://docs.python.org/3/library/functions.html#enumerate
运行在线:
推荐答案
任何迭代器都是一次性,当它完全执行时,它变为空,不能再使用了。当你调用 logging.debug(list(e))
时,你已经在list()函数中使用它并因此耗尽它。因此,以下尝试在中使用
循环不会产生任何效果。
Any iterator is "one-shot" in sense that, when it is fully executed, it becomes empty and can't be used anymore. When you called logging.debug( list(e) )
, you have used it in the list() function and so exhausted it. So, the following attempt to use it in for
cycle gives nothing.
当enumerate()是修改后的代码时在此调试之后再次调用,脚本行为会发生变化 - 它会在 y [int(k)]上引发IndexError。附加(v)
;我不会为你解决这个问题,但这足以表明循环体开始执行了。
With modified code when enumerate() is called again after this debug, the script behavior gets changed - it raises IndexError on y[int(k)].append( v )
; I won't fix this for you but this is enough sign that cycle body begins being executed.
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