无法发送内容体与这个动词型与GET请求

问题描述

我目前正在接受通过的WebAPI的请求，并试图只需将它重新发送到另一个站点。

I'm currently receiving a request through the WebApi, and trying to just resend it to another site.

的目的是接收的请求，由例如：的http：//本地主机：9999 /＃q构成=测试。然后它着真正的网站：（我的测试，我设置google.com） http://google.com /＃Q =测试

The goal is to receive a request, by example: http://localhost:9999/#q=test. And then forward it to the real site:(for my test I set google.com) http://google.com/#q=test

我有以下code：

    protected override async Task<HttpResponseMessage> SendAsync(HttpRequestMessage request, System.Threading.CancellationToken cancellationToken)
    {
        string url = request.RequestUri.PathAndQuery;
        UriBuilder forwardUri = new UriBuilder(_otherWebSiteBase);
        forwardUri.Path = url;
        if (request.Method == HttpMethod.Get)
        {
            //request.Method = HttpMethod.Post;
        }
        request.RequestUri = forwardUri.Uri;
        request.Headers.Host = forwardUri.Host;
        return await _client.SendAsync(request, HttpCompletionOption.ResponseHeadersRead);//_client is an HttpClient
    }

目前我得到了一个 System.Net.ProtocolViolationException 的规定：无法用这个动词型发送的内容体。

Currently I got an System.Net.ProtocolViolationException which states:Cannot send a content-body with this verb-type.

但我的输入请求是GET请求（也应该是一个GET请求）。如果我把一个POST请求，我没有异常了，但谷歌表示，他们不希望一个POST请求。

But my input request is a GET request(and should be a GET request). If I put a POST request, I don't have an exception anymore, but google says that they don't expect a POST request.

那么，为什么这个异常来了吗？就如何解决它的主意？

So why is this exception coming? Any idea on how to fix it?

推荐答案

我最终通过创建初始请求的副本，并重新发送它：

I ended by creating a copy of the initial request, and sending it again:

protected override async Task<HttpResponseMessage> SendAsync(HttpRequestMessage request, System.Threading.CancellationToken cancellationToken)
{
    string url = request.RequestUri.PathAndQuery;
    UriBuilder forwardUri = new UriBuilder(_otherWebSiteBase);
    forwardUri.Path = url;

    HttpRequestMessage newRequest = request.Clone(forwardUri.Uri.ToString());

    HttpResponseMessage responseMessage = await _client.SendAsync(newRequest);
    return responseMessage;
}

的克隆方法如下，从这个问题主要是启发：<一href="https://stackoverflow.com/questions/21467018/how-to-forward-an-htt$p$pquestmessage-to-another-server">How转发的Htt的prequestMessage到另一台服务器

    public static HttpRequestMessage Clone(this HttpRequestMessage req, string newUri)
    {
        HttpRequestMessage clone = new HttpRequestMessage(req.Method, newUri);

        if (req.Method != HttpMethod.Get)
        {
            clone.Content = req.Content;
        }
        clone.Version = req.Version;

        foreach (KeyValuePair<string, object> prop in req.Properties)
        {
            clone.Properties.Add(prop);
        }

        foreach (KeyValuePair<string, IEnumerable<string>> header in req.Headers)
        {
            clone.Headers.TryAddWithoutValidation(header.Key, header.Value);
        }
        clone.Headers.Host = new Uri(newUri).Authority;
        return clone;
    }

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