问题描述
当我使用正则表达式时，显然Java的正则表达式将变音符号和其他特殊字符计为非单词字符。
Apparently Java's Regex flavor counts Umlauts and other special characters as non-"word characters" when I use Regex.
"TESTÜTEST".replaceAll( "\\W", "" )
返回TESTTEST我。我想要的只是删除所有真正的非单词字符。任何方式都可以做到这一点，而不是像
returns "TESTTEST" for me. What I want is for only all truly non-"word characters" to be removed. Any way to do this without having something along the lines of
"[^A-Za-z0-9äöüÄÖÜßéèáàúùóò]"
只是意识到我忘了ô？
推荐答案
使用 [^ \p {L} \p {Nd}] + - 这匹配所有（Unicode）字符字母也不是（十进制）数字。
Use [^\p{L}\p{Nd}]+ - this matches all (Unicode) characters that are neither letters nor (decimal) digits.
在Java中：
String resultString = subjectString.replaceAll("[^\\p{L}\\p{Nd}]+", "");
修改：
我将 \p {N} 更改为 \p {Nd} 因为前者也匹配某些数字符号，如¼;后者没有。请在上查看。
I changed \p{N} to \p{Nd} because the former also matches some number symbols like ¼; the latter doesn't. See it on regex101.com.
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