问题描述
我很难保存多条记录。我已经尝试了上百万种方法,但最终还是遇到了同样的问题:我的记录未保存,并且看不到任何错误。请记住,我是Cakephp的新手和新手。
I'm having the hardest time with saving multiple records. I've tried a million things, but I end up with the same problem: my records are not saved and I can't see any errors. Bear in mind that I'm new to cakephp and a novice coder.
我错过了一些显而易见且至关重要的东西吗?
Am I missing something obvious and crucial?
表:
$this->table('splits');
$this->displayField('id');
$this->primaryKey('id');
$this->belongsTo('Transactions', [
'foreignKey' => 'transaction_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Accounts', [
'foreignKey' => 'account_credit_id',
'joinType' => 'INNER'
]);
控制器:
$splits = $this->Splits->newEntity();
if ($this->request->is('post')) {
$splits = $this->Splits->newEntities($this->request->data());
debug($splits);
foreach ($splits as $split){
$this->Splits->save($split);
}
}
$transactions = $this->Splits->Transactions->find('list', ['limit' => 200]);
$accounts = $this->Splits->Accounts->find('list', ['limit' => 200]);
$this->set(compact('split', 'transactions', 'accounts'));
$this->set('_serialize', ['split']);
模板:
echo $this->Form->input('Splits.1.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.1.amount', ['type' => 'float']);
echo $this->Form->input('Splits.1.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.2.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.2.amount', ['type' => 'float']);
echo $this->Form->input('Splits.2.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.3.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.3.amount', ['type' => 'float']);
echo $this->Form->input('Splits.3.account_id', ['options' => $accounts]);
调试$ splits:
Debug on $splits:
[
(int) 0 => object(App\Model\Entity\Split) {
(int) 1 => [
'transaction_id' => '108',
'amount' => '100.33',
'account_id' => '2'
],
(int) 2 => [
'transaction_id' => '108',
'amount' => '50.22',
'account_id' => '4'
],
(int) 3 => [
'transaction_id' => '108',
'amount' => '65.22',
'account_id' => '5'
],
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
(int) 1 => true,
(int) 2 => true,
(int) 3 => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'Splits'
}
]
推荐答案
您是否曾经在某处看到正在使用此 Table.index.field
样式,或者您是否只是尝试过一些东西并希望它能工作?
Did you somewhere saw this Table.index.field
style being used, or did you just tried something and hoped it would work?
保存许多分别创建许多实体的记录时,期望的格式是一个数字索引的数组,其中包含各个记录的数据,就像文档中所示
When saving many records respectively creating many entities, the expected format is a numerically indexed array that holds the data for the individual records, just as shown in the docs
Cookbook > Database Access & ORM > Saving Data > Converting Multiple Records
[...]
在这种情况下,多篇文章的请求数据应像
一样:
In this situation, the request data for multiple articles should look like:
$data = [
[
'title' => 'First post',
'published' => 1
],
[
'title' => 'Second post',
'published' => 1
],
];
因此,您的输入不应使用表名,而应使用表名索引和字段名称,例如
So your inputs should not use the table name, but just the index and the field name, like
echo $this->Form->input('0.transaction_id', /* ... */);
echo $this->Form->input('0.amount', /* ... */);
echo $this->Form->input('0.account_id', /* ... */);
echo $this->Form->input('1.transaction_id', /* ... */);
echo $this->Form->input('1.amount', /* ... */);
echo $this->Form->input('1.account_id', /* ... */);
echo $this->Form->input('2.transaction_id', /* ... */);
echo $this->Form->input('2.amount', /* ... */);
echo $this->Form->input('3.account_id', /* ... */);
这篇关于cakephp 3.x保存多个实体-newEntities的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!