如何计算OpenCV中矩阵的直方图？

问题描述

我有一个由从 0到N 的整数组成的矩阵，我想要获得一个大小 N + 1 其中每个元素都有每个数字的出现次数。

I have a matrix that consists of integers from 0 to N, and I want to obtain a data matrix of size N+1 where each element has the number of occurences of each number.

所以如果输入矩阵是

0 0 0
1 1 0
0 0 2

那么我的输出应该是

// occurences of  0  1  2
hist           = [6, 2, 1]

有一个简单的C ++ OpenCV，像MATLAB中的 hist 函数？

Is there an easy (built-in) way to accomplish this in C++ OpenCV, like the hist function in MATLAB?

谢谢！

推荐答案

此代码从图像中读取所有灰度值，并导致频繁出现的值（发生的值的次数）。即

This code reads all the grayscale values from an image and results in frequent occurring values (Number of times the value as occurred). i.e

出现像素值'0'的次数，

Number of times pixel value '0' as appeared,

像素值'1'出现，...&所以一直到256.

Number of times pixel value '1' as appeared, ... & so on till 256.

#include <opencv\cv.h>
#include <highgui\highgui.hpp>
using namespace std;
using namespace cv;
    int main()
{
cv::Mat img = cv::imread("5.jpg",0);

//for(int j=0;j<img.rows;j++)
//{
//  for (int i=0;i<img.cols;i++)
//  {
//    int a;
//  a=img.at<uchar>(j,i);
//     cout<<a<<endl;
//  }
//}
vector<int> values_rgb;
for(int i=0; i<20; i++)
{
    for(int j=0; j<20; j++)
    {
        int value_rgb = img.at<uchar>(i,j);
        values_rgb.push_back(value_rgb);
        //cout << "(" << i << "," << j << ") : " << value_rgb <<endl;
    }
}
// Sorting of values in ascending order
vector<int> counter_rg_values;
for(int l=0; l<256; l++)

{
    for(int k=0; k<values_rgb.size(); k++)
    {
        if(values_rgb.at(k) == l)
        {
            counter_rg_values.push_back(l);
        }
    }
}
//for(int m=0;m<counter_rg_values.size();m++)
//cout<<m<<" "<< counter_rg_values[m] <<endl;
int m=0;
for(int n=0;n<256;n++)
{
    int c=0;
    for(int q=0;q<counter_rg_values.size();q++)
    {
        if(n==counter_rg_values[q])
        {
            //int c;
        c++;
        m++;
        }
    }

    cout<<n<<"= "<< c<<endl;
}
cout<<"Total number of elements "<< m<<endl;

cv::imshow("After",img);
waitKey(0);
}

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