问题描述
有没有办法在 Unix 中删除文件中的重复行?
Is there a way to delete duplicate lines in a file in Unix?
我可以使用 sort -u 和 uniq 命令来完成，但我想使用 sed 或 awk>.
I can do it with sort -u and uniq commands, but I want to use sed or awk.
这可能吗?
推荐答案
awk '!seen[$0]++' file.txt
seen 是一个关联数组，AWK 会将文件的每一行传递给它.如果某行不在数组中，则 seen[$0] 将评估为 false.! 是逻辑 NOT 运算符，它将把 false 反转为 true.AWK 将打印表达式计算结果为真的行.
seen is an associative array that AWK will pass every line of the file to. If a line isn't in the array then seen[$0] will evaluate to false. The ! is the logical NOT operator and will invert the false to true. AWK will print the lines where the expression evaluates to true.
++ 递增 seen 以便 seen[$0] == 1 在第一次找到一行之后 >seen[$0] == 2，依此类推.AWK 将除 0 和 ""(空字符串)以外的所有内容评估为真.如果在 seen 中放置了重复的行，则 !seen[$0] 将评估为 false，并且该行不会写入输出.
The ++ increments seen so that seen[$0] == 1 after the first time a line is found and then seen[$0] == 2, and so on.AWK evaluates everything but 0 and "" (empty string) to true. If a duplicate line is placed in seen then !seen[$0] will evaluate to false and the line will not be written to the output.
这篇关于如何删除文件中的重复行而不在Unix中对其进行排序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！