Python:词典列表:如何使用sys.stdout进行漂亮的打印输出

问题描述

我有以下词典列表:

[{'Sequence': 'TGACCCTGCTTGGCGATCCCGGCGTTTC', 'Start': '52037', 'Strand': '+', 'End': '52064'}, {'Sequence': 'TGATCGCGCAACTGCAGCGGGAGTTAC', 'Start': '188334', 'Strand': '+', 'End': '188360'}, {'Sequence': 'TGATCCGGCACTCGTTGGAGTTCGTATC', 'Start': '245882', 'Strand': '+', 'End': '245909'}, {'Sequence': 'TGACCTTGGTCAGATCGATGACCGTAAT', 'Start': '318422', 'Strand': '+', 'End': '318449'}, {'Sequence': 'TGACCCGCGTATTTTGGAGCAGAAGTATC', 'Start': '343421', 'Strand': '+', 'End': '343449'}, {'Sequence': 'TGATCCGGCACTCGTTGGAGTTCGTATC', 'Start': '359576', 'Strand': '+', 'End': '359603'}, {'Sequence': 'TGATCGGCAATTCCTATGGCAAGTATC', 'Start': '457457', 'Strand': '+', 'End': '457483'}, {'Sequence': 'TGATCGAGGCGCCAGTTGTGCCCGTATT', 'Start': '627296', 'Strand': '+', 'End': '627323'}, {'Sequence': 'TGATCCAAGTGAACCCCCGCCCAGTAAA', 'Start': '637265', 'Strand': '+', 'End': '637292'}, {'Sequence': 'TGACCGGAAGACCGCCGTCGAGCGTATC', 'Start': '829035', 'Strand': '+', 'End': '829062'}, {'Sequence': 'TGATCGCGGCACCGACACCGGTCGTAAT', 'Start': '864440', 'Strand': '+', 'End': '864467'}, {'Sequence': 'TGATCGTTTCCGTGCTCGGAGCGTATC', 'Start': '934160', 'Strand': '+', 'End': '934186'}, {'Sequence': 'TGACCTGGCTCGAGGCCTGAGGAGTAAA', 'Start': '1162006', 'Strand': '+', 'End': '1162033'}, {'Sequence': 'TGACCCGCCGCAACATCCCCTTCGTAAA', 'Start': '1294515', 'Strand': '+', 'End': '1294542'}]

我想获取以下输出(通过sys.stdout重定向打印):

I would like to acquire the following output (redirecting prints via sys.stdout):

Start:1234  End:5678  Strand:+  Sequence:ABCDEFG
...

到目前为止，我的想法是循环遍历列表，并使用 get-method 获取键的值，然后进行手动打印，基本上是这样的:

So far, my idea involves looping through the list and using the get-method to get the value of the key and then do a manual printout, basically like this:

for item in dictList:
    print("Start"+item.get('Start'))
    print("End"+item.get('End'))
    ...

我不确定如何处理换行符.我读了有关sys.stdout刷新的内容，以避免换行符，但是由于我不想避免所有换行符，因此不确定是否符合我的目标.

I am not sure how to deal with the newlines though. I read about sys.stdout flush to avoidnewlines, but since I do not want to avoid all newlines, I am not sure if this would suit my aim.

有更聪明/更短的方法吗?

Is there a smarter/shorter way to do this?

感谢Aleksey，我想将我的印刷声明更改为:

Thanks to Aleksey, I thought of changing my print statement to:

for item in dictList:
    print("Start"+str(item.get('Start'))+"  "+"End"+str(item.get('End'))+"  "+"Strand"+str(item.get('Strand'))+"  "+"Sequence: "+str(item.get('Sequence')))

Update2

到目前为止，我坚持这样做:

Update2

so far, I am sticking to this:

print(ecf+"  "+replicon+"  -  "+"Validated results: Total number of hits: "+str(len(finalList)))
print("")

for item in finalList:
    print("Start: "+str(item.get('Start'))+"  "+"End: "+str(item.get('End'))+"  "+"Strand: "+str(item.get('Strand'))+"  "+"Sequence: "+str(item.get('Sequence')))

打印:

ECF02  pSymA  -  Validated results: Total number of hits: 284

Start: 2876  End: 2903  Strand: +  Sequence: GAACTACAGGAAGTTCATGGTCTCCTTC
Start: 2876  End: 2900  Strand: +  Sequence: GAACTACAGGAAGTTCATGGTCTCC
Start: 9214  End: 9238  Strand: +  Sequence: GAACGTCGGGCGCAAGAGCCGCTTT
...

请注意:dictList被finalList取代.由于我的脚本的某些部分在打印之前就已运行

please note: dictList was replaced by finalList. Due to parts of my script running before those prints

推荐答案

您可以使用 .format_map(each_dic)或更高版本的Python 3.5+添加替代方法 .format(** each_dic).使用每种格式的打印列表中的每个字典.

You could use .format_map(each_dic) or later Python 3.5+ added alternative .format(**each_dic). Uses each dict in the list in each print with formatting.

for each_dic in dictList:
    print('Sequence: {Sequence:<29} '
          'Start: {Start:>7} '
          'Strand: {Strand} '
          'End: {End:>7}'.format_map(each_dic))

查看Python帮助页面:字符串-常见的字符串操作参考和示例.

Look at Python help page: string - Common string operations for further reference and examples.

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