问题描述
我的情况:
在Laravel 4/5中,如何在一个与该表相关联的字段中排列表格结果?我有用户
,只存储电子邮件
和密码
字段。但是我有另一个表的细节
存储名称
,生日
等...
如何获取用户
表结果按 details.name
?
PS:由于用户是一个具有许多其他关系并有很多项目的中心表, t只做一个反向搜索,如 Details :: ...
我建议使用join。 (模型应以单数形式命名;用户;细节)
$ users = User :: join('details' 'users.id','=','details.user_id')//'details'和'users'是表名;不是模型名称
- > orderBy('details.name','asc')
- > get();
如果您多次使用此查询,可以将其保存在Model中的范围内。 p>
类用户扩展\Eloquent {
public function scopeUserDetails($ query){
return $ query-> ; join('details','users.id','=','details.user_id')
}
}
然后从控制器调用查询。
$ users = User :: userDetails() - > orderBy('details.name','asc') - > get();
In Laravel 4/5 how can order a table results based in a field that are connected to this table by a relationship?
My case:
I have the users
that only store the e-mail
and password
fields. But I have an another table called details
that store the name
, birthday
, etc...
How can I get the users
table results ordering by the details.name
?
P.S.: Since users is a central table that have many others relations and have many items, I can't just make a inverse search like Details::...
I would recommend using join. (Models should be named in the singular form; User; Detail)
$users = User::join('details', 'users.id', '=', 'details.user_id') //'details' and 'users' is the table name; not the model name
->orderBy('details.name', 'asc')
->get();
If you use this query many times, you could save it in a scope in the Model.
class User extends \Eloquent {
public function scopeUserDetails($query) {
return $query->join('details', 'users.id', '=', 'details.user_id')
}
}
Then call the query from your controller.
$users = User::userDetails()->orderBy('details.name', 'asc')->get();
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