如何读取间距不均匀的数据?

问题描述

我的数据似乎没有一致的间距或定位.它看起来像:

I have data which doesn't appear to have consistent spacings or positioning. It looks like:

1675 C Street , Suite 201
Anchorage   AK  99501
61.205475   -149.886882
600 Azalea Road
Mobile    AL      36609
30.656824   -88.148781
1601 Harbor Bay Parkway , Suite 150
Alameda   CA    94502
37.726114   -122.240546
1900 Point West Way,  Suite 270
Sacramento      CA  95815
38.5994175  -121.4315844
3600 Wilshire Blvd., Suite 1500
Los Angeles   CA    90010
34.06153    -118.303463

我想从中提取街道地址、城市名称、州、邮政编码、纬度和经度.我认为下面的代码可以工作，但它产生了非常奇怪的结果.

From this I'd like to extract the street address, city name, state, zip code, lat, and long. I thought the following code would work, but it produces very weird results.

data voa;
    input Address $50.;
    input City $ State $ Zip;
    input Latitude Longitude;
    datalines;

我认为问题在于元素的间距或位置不一致.

I think the issue comes from the fact that there isn't consistent spacing or positioning of the elements.

推荐答案

您的数据可以使用 LIST 输入正常工作，您只需要添加查找双分隔符选项"&到 CITY 再加上它需要多一点 16 美元左右.

Your data will work fine using LIST input you just need to add the "look for double delimiter option" & to CITY plus it need to be a bit longer $16 or so.

input City &$16. State $ Zip;

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