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问题描述
我编写了一个简单的 httprequest/response 代码,但出现以下错误.我在我的类路径中引用了 httpclient、httpcore、common-codecs 和 common-logging.我对java很陌生,不知道这里发生了什么.请帮我.
I have written a simple httprequest/response code and I am getting this below error. I have referenced httpclient, httpcore, common-codecs and common-logging in my classpath. I am very new to java and have no clue what is going on here. Please help me.
代码:
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.HttpResponse;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.Header;
import org.apache.http.HttpHeaders;
public class UnshorteningUrl {
public static void main(String[] args) throws Exception
{
HttpGet request=null;
HttpClient client = HttpClientBuilder.create().build();
try {
request = new HttpGet("trib.me/1lBFzSi");
HttpResponse httpResponse=client.execute(request);
Header[] headers = httpResponse.getHeaders(HttpHeaders.LOCATION);
// Preconditions.checkState(headers.length == 1);
String newUrl = headers[0].getValue();
System.out.println("new url" + newUrl);
} catch (IllegalArgumentException e) {
// TODO: handle exception
}finally {
if (request != null) {
request.releaseConnection();
}
}
}}
错误:
Exception in thread "main" org.apache.http.client.ClientProtocolException
at org.apache.http.impl.client.InternalHttpClient.doExecute(InternalHttpClient.java:186)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:82)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:106)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:57)
at UnshorteningUrl.main(UnshorteningUrl.java:26)
Caused by: org.apache.http.ProtocolException: Target host is not specified
at org.apache.http.impl.conn.DefaultRoutePlanner.determineRoute(DefaultRoutePlanner.java:69)
at org.apache.http.impl.client.InternalHttpClient.determineRoute(InternalHttpClient.java:124)
at org.apache.http.impl.client.InternalHttpClient.doExecute(InternalHttpClient.java:183)
... 4 more
推荐答案
错误信息有点误导.您提供的值不代表完整的 URI
The error message is kind of misleading. You've provided a value that does not represent a complete URI
request = new HttpGet("trib.me/1lBFzSi");
缺少协议.
只需提供一个完整的 URI
Simply provide a complete URI
request = new HttpGet("http://trib.me/1lBFzSi");
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