使用XSLT做枢轴

问题描述

我有一个像这样的xml文件:

I have an xml file like this:

<root>
    <item>
        <name>one</name>
        <status>good</status>
    </item>
    <item>
        <name>two</name>
        <status>good</status>
    </item>
    <item>
        <name>three</name>
        <status>bad</status>
    </item>
    <item>
        <name>four</name>
        <status>ugly</status>
    </item>
    <item>
        <name>five</name>
        <status>bad</status>
    </item>
</root>

我想使用XSLT对其进行转换，以获得类似的内容:

I want to transform this using XSLT to get something like:

<root>
    <items><status>good</status>
        <name>one</name>
        <name>two</name>
    </items>
    <items><status>bad</status>
        <name>three</name>
        <name>five</name>
    </items>
    <items><status>ugly</status>
        <name>four</name>
    </items>
</root>

换句话说，我得到一个项目列表，每个项目都有一个状态，并且我想将其变成一个状态列表，每个状态都有一个项目列表.

In other words, I get a list of items, each with a status, and I want to turn it into a list of statuses, each with a list of items.

我最初的想法是依次制作与每种状态类型匹配的应用模板，但这意味着我必须知道状态的完整列表.有更好的方法吗?

My initial thought was to do apply-templates matching each status type in turn, but that means I have to know the complete list of statuses. Is there a better way to do it?

感谢您的帮助.

推荐答案

默默营救！

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

    <xsl:key name="muench" match="/root/item/status" use="."/>

    <xsl:template match="/">
        <root>
        <xsl:for-each select="/root/item/status[generate-id() = generate-id(key('muench',.)[1])]">
            <xsl:call-template name="pivot">
                <xsl:with-param name="status" select="."/>
            </xsl:call-template>
        </xsl:for-each>
        </root>
    </xsl:template>

    <xsl:template name="pivot">
        <xsl:param name="status"/>
        <items>
            <status><xsl:value-of select="$status"/></status>
            <xsl:for-each select="/root/item[status=$status]">
                <name><xsl:value-of select="name"/></name>
            </xsl:for-each>
        </items>
    </xsl:template>

</xsl:stylesheet>

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