为何_popen在这里起作用，而boost :: process却不起作用?

问题描述

在Windows上，我使用_popen具有以下工作代码，

I have the following working code using _popen, on windows,

m_pGNUPlot = _popen("/gnuplot/bin/gnuplot.exe", "w");
fprintf(m_pGNUPlot, "set term win\n");
fprintf(m_pGNUPlot, "set term pngcairo\n");
fprintf(m_pGNUPlot, "plot \"\Data.txt\" using 1:2 notitle\n");
fprintf(m_pGNUPlot, "set output \"\Out.png\"\n");
fprintf(m_pGNUPlot, "replot\n");
fflush(m_pGNUPlot);

但是问题是cmd窗口不断弹出，并且没有办法阻止它()因此，我在boost :: process

But the problem with this is that cmd window keeps poping up, and there is no way to prevent that (Link)So, I write the equivalent code in boost::process

bp::pipe m_Write;
bp::environment env = boost::this_process::environment();
m_Plot = new bp::child("/gnuplot/bin/gnuplot.exe", bp::std_in < m_Write, env, boost::process::windows::hide);
m_Write.write("set term win\n", sizeof(char)*14);
m_Write.write("set term pngcairo\n", sizeof(char) * 19);
m_Write("plot \"\Data.txt\" using 1:2 notitle\n", sizeof(char)*35);
m_Write("set output \"\Out.png\"\n", sizeof(char)*22);
m_Write.write("replot\n", sizeof(char) * 8);

所以，我的问题是-两个代码段是否等效?如果是这样，为什么第二个不起作用?

So, my question is - are the two code snippets equivalent? And if so, why might the second one not work?

推荐答案

我没有Windows，因此我在Linux机器上对其进行了测试，略有简化:

I don't have windows, so I tested it on my linux box, slightly simplified:

#include <boost/process.hpp>
#include <iostream>

namespace bp = boost::process;

int main() {
    bp::opstream m_Write;
    boost::filesystem::path program("/usr/bin/gnuplot");
    bp::child m_Plot(program, bp::std_in = m_Write);

    m_Write << "set term png\n";
    m_Write << "set output \"Out.png\"\n";
    m_Write << "plot \"Data.txt\" using 1:2 notitle\n";
    m_Write.flush();
    m_Write.pipe().close();

    m_Plot.wait();
    std::cout << "Done, exit code: " << m_Plot.exit_code() << "\n";
}

打印:

Done, exit code: 0

并从简单数据中创建了这张漂亮的图片:

And created this nice image from simplistic data:

在Windows上，利用Boost Filesystem的path的功能执行路径:

On windows, leverage the power of Boost Filesystem's path to do the path:

boost::filesystem::path program("C:\\gnuplot\\bin\\gnuplot.exe");

其他说明

如果整个脚本确实是固定的，请考虑使用原始文字:

Other Notes

If the whole script is, indeed, fixed, consider using a raw literal:

m_Write << R"(set term png
    set output "Out.png"
    plot "Data.txt" using 1:2 notitle)" << std::flush;
m_Write.pipe().close();

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