本文介绍了C# - 将 .txt 文件读入文本框的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用以下代码将 .txt 文件读入多行文本框中.我已经让文件对话框按钮完美工作,但我不确定如何将文件中的实际文本获取到文本框中.这是我的代码.你能帮忙吗?

I am trying to read a .txt file into a multi-line text box with the following code. I have gotten the file dialog button to work perfectly, but I am not sure how to get the actual text from the fiile into the textbox. Here is my code. Can you help?

private void button_LoadSource_Click(object sender, EventArgs e)
    {
        Stream myStream = null;
        OpenFileDialog openFileDialog1 = new OpenFileDialog();

        openFileDialog1.InitialDirectory = "c:\";
        openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
        openFileDialog1.FilterIndex = 2;
        openFileDialog1.RestoreDirectory = true;

        if (openFileDialog1.ShowDialog() == DialogResult.OK)
        {
            try
            {
                if ((myStream = openFileDialog1.OpenFile()) != null)
                {
                    using (myStream)
                    {
                        // Insert code to read the stream here.
                    }
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
            }
        }
    }

推荐答案

如果你只需要完整的文本,你应该使用函数File.ReadAllText - 将对话框中选择的文件名/路径传递给它 (openFileDialog1.FileName).

if you just need the complete text, you should use the function File.ReadAllText - pass it the FileName/Path selected in the dialoge (openFileDialog1.FileName).

例如要将内容加载到文本框中,您可以编写:

to load for example the content into a textbox, you can write:

 textbox1.Text = File.ReadAllText(openFileDialog1.FileName);

打开和使用流有点复杂,你应该查看 using - 语句

opening and using streams is a little bit more complicated, for that you should look up the using - statement

这篇关于C# - 将 .txt 文件读入文本框的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-25 20:48