数据在数据库中输入错误

本文介绍了数据在数据库中输入错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我创建了一个表单，现在我想在数据库中提交它的数据。我有以下代码 <？php $ dbconn = new MySQLi（ localhost， root， ， Tajweed）; { $ pname = mysqli_real_escape_string（$ dbconn，$ _POST [' pname']）; $ plink = mysqli_real_escape_string（$ dbconn，$ _POST [' PLINK']）; $ sql = $ dbconn-> query（ INSERT INTO main_page（pname，plink）VALUES（' $ PNAME， '$ PLINK'））; } ？> < 表格 name = myForm action = <？php $ _PHP_SELF？> 方法 = 发布 > 页面名称：< 输入 类型 = text 占位符 = 页面名称： 名称 = pname / > 页面链接：< 输入 type = text 占位符 = 页面链接： 名称 = plink / > < input type = 提交 value = 提交 > < / form > < pre lang = PHP > < 预 lang = PHP > 当我运行此代码时，它会给出错误 un-deafind index：pname和plink 请帮我解决问题。 我尝试了什么： $ dbconn =新的MySQLi（localhost，root，，Tajweed）; { $ pname = mysqli_real_escape_string（$ dbconn，$ _POST ['pname']）; $ plink = mysqli_real_escape_string（$ dbconn，$ _POST ['plink']）; $ sql = $ dbconn-> query（INSERT INTO main_page（pname，plink）VALUES（'$ pname' ，'$ plink'））; } ？> < form name =myFormaction =method =post> 页面名称：<输入type =textplaceholder =page name：name =pname/> 页面链接：< input type =textplaceholder =Page Link：name =plink /> < input type =submitvalue =submit> < / form> i尝试此代码解决方案 dbconn = 新 MySQLi（ localhost， root， ， Tajweed）; { pname = mysqli_real_escape_string（ dbconn， I created a Form and now i want to submit it's data in the Database. i have the following code <?php$dbconn = new MySQLi("localhost","root","","Tajweed");{ $pname = mysqli_real_escape_string($dbconn, $_POST['pname']);$plink = mysqli_real_escape_string($dbconn, $_POST['plink']); $sql=$dbconn->query("INSERT INTO main_page (pname,plink) VALUES('$pname','$plink')");}?><form name="myForm" action="<?php $_PHP_SELF ?>" method="post">Page Name: <input type="text" placeholder="page name :" name="pname" />Page Link: <input type="text" placeholder="Page Link :" name="plink" /><input type="submit" value="submit"></form><pre lang="PHP"><pre lang="PHP">when i run this code it's give an error thatun-deafind index: "pname" and "plink"please help me to solve the problem.What I have tried:$dbconn = new MySQLi("localhost","root","","Tajweed");{ $pname = mysqli_real_escape_string($dbconn, $_POST['pname']);$plink = mysqli_real_escape_string($dbconn, $_POST['plink']); $sql=$dbconn->query("INSERT INTO main_page (pname,plink) VALUES('$pname','$plink')");}?><form name="myForm" action="" method="post">Page Name: <input type="text" placeholder="page name :" name="pname" />Page Link: <input type="text" placeholder="Page Link :" name="plink" /><input type="submit" value="submit"></form>i tried this code 解决方案 dbconn = new MySQLi("localhost","root","","Tajweed");{ pname = mysqli_real_escape_string(dbconn, 这篇关于数据在数据库中输入错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！