寻找最接近的90度角点

问题描述

我已经走了很远，但是似乎有些不起作用.

I've gotten pretty far but something just doesn't seem to work.

A = 50.88259382849774,6.003988087177277
B = 50.88269282423443,6.0036662220954895
C = 50.882530369581545,6.003847271203995

C坐标与90度线(x)略有不同，我制作的此函数应将C定位在最接近x线的位置.

The C coordinate is a little off from the 90 degree line (x) and this function I made should position C on the closest way to the x line.

this.snapCoords = function(a, b, c){
    var result = (b.x-a.x)*(c.x-b.x)+(b.y-a.y)*(c.y-b.y);

    var negative = false;
    if(result < 0){
        result = result*-1;
        negative = true;
    }
    result = Math.sqrt(result);
    result = result/2;

    if(negative === false){
        var d = {x: c.x+result, y: c.y-result};
    }
    else{
        var d = {x: c.x-result, y: c.y+result};
    }

    console.log(d); // returns : 50.88246729610898,6.003910344676565
}

它确实获得了90度(x)线，但没有最接近的方式.我的功能肯定仍然有问题，但我无法弄清楚.

It does get the the 90 degree (x) line but not the closest way. Something must still be wrong in my function but I can't figure it out.

所以这是我的问题

我的函数将第三个坐标放置在C上，该坐标为90度，但不在它应该以任何方式延伸到另一点的位置(红点).

My function puts the third coordinate on C which is 90 degrees but not where it should be (the red spot) it somehow extends to a further point.

推荐答案

我认为OP试图将点C投影到通过点B的线上，并且垂直于线AB.在这种情况下，投影的数学不正确.您可以找到投影点D为

I think the OP is trying to project the point C onto the line passing thru point B and is perpendicular to line AB. If this is the case, the math for the projection is not correct. You can find the projected point D as

D = C-点(vec(BC)，vec(AB))* vec(AB)/| vec(AB)| ^ 2

D= C - dot(vec(BC), vec(AB)) * vec(AB)/|vec(AB)|^2

通过此计算，投影点D将为(50.8825952820492，6.00363622113846).

By this calculation, the projected point D will be (50.8825952820492, 6.00363622113846).

下面是A，B，C和D点的图片:

The following is a picture for points A, B, C and D :

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