问题描述
假设我们在C ++中有一个SDK接受一些二进制数据（如图片）并做某事。是不可能使这个SDK防撞？崩溃我主要意味着由于用户传递的无效输入（如异常短的垃圾数据），由于操作系统对内存访问冲突的强制终止。
Let's say we have an SDK in C++ that accepts some binary data (like a picture) and does something. Is it not possible to make this SDK "crash-proof"? By crash I primarily mean forceful termination by the OS upon memory access violation, due to invalid input passed by the user (like an abnormally short junk data).
我没有C ++的经验，但是当我使用Google搜索时，我发现几个手段听起来像一个解决方案（使用向量而不是数组，配置编译器执行自动边界检查等）。
I have no experience with C++, but when I googled, I found several means that sounded like a solution (use a vector instead of an array, configure the compiler so that automatic bounds check is performed, etc.).
当我向开发人员介绍这一点时，他说这还是不可能的..不是我不相信他，但如果是这样，处理这个？我认为JVM每次执行边界检查。如果是这样，为什么不能在C ++中手动做同样的事情？
When I presented this to the developer, he said it is still not possible.. Not that I don't believe him, but if so, how is language like Java handling this? I thought the JVM performs everytime a bounds check. If so, why can't one do the same thing in C++ manually?
UPDATE
我不是说应用程序不会终止。我的意思是它不应该突然终止没有发生什么的信息（我的意思是它会转储核心等，但是是不可能显示一条消息，如参数x是无效的等等。）
UPDATE
By "Crash proof" I don't mean that the application does not terminate. I mean it should not abruptly terminate without information of what happened (I mean it will dump core etc., but is it not possible to display a message like "Argument x was not valid" etc.?)
推荐答案
您可以在C ++中检查数组的边界，std :: vector在（）自动执行此操作
You can check the bounds of an array in C++, the std::vector at() does this automatically
这不会使你的应用程序崩溃的证明，你仍然允许故意拍摄自己在脚，但没有什么在c ++强制你拉扳机
This doesn't make your app crash proof, you are still allowed to deliberately shoot yourself in the foot but nothing in c++ forces you to pull the trigger
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