为什么我出现“错误"命令不同步；您不能立即运行此命令"

问题描述

标题中提到的错误文档

例如，如果您使用的是mysql_use_result()和 在调用mysql_free_result()之前，尝试执行一个新查询. 如果您尝试执行两个返回数据的查询，也会发生这种情况 而不在两者之间调用mysql_use_result()或mysql_store_result().

This can happen, for example, if you are using mysql_use_result() and try to execute a new query before you have called mysql_free_result(). It can also happen if you try to execute two queries that return data without calling mysql_use_result() or mysql_store_result() in between.

从此处: http://dev .mysql.com/doc/refman/5.0/en/commands-out-of-sync.html

但是在第一个查询中，我没有从mysql数据库中获取任何数据，我只是在插入.在第二次查询中，我从数据库中获取数据.

But In First Query I am not fetching any data from mysql database, I am just inserting. And In second Query I am getting the data from database.

这是我的代码

$connection = mysqli_connect("localhost","username","password","tbl_msgs");
if(mysqli_connect_errno($connection))
{
    die("Failed to connect to MySQL: " . mysqli_connect_error());
}
$query = "INSERT INTO users (total_comments, total_views)
          VALUES ({$total_comments}, {$total_views});";

$query .= "INSERT INTO msgs (notifications) VALUES ({$notifications})";

mysqli_multi_query($connection,$query);

到目前为止，一切都很好.但是当我执行以下查询时，它给出了错误

Upto this Step every thing is fine. But When I execute the following query It gives the Error

$select_query = "SELECT * FROM msgs WHERE msg_id = {$msg_id}";

$result_set = mysqli_query($connection,$select_query);

if(!$result_set) {
    die(mysqli_error($connection));
}

在这里给出错误Commands out of sync; you can't run this command now.我无法理解这种情况

Here it gives the Error Commands out of sync; you can't run this command now. I can't understand this situation

注意:查询中有任何问题，我已经直接对PHPMyAdmin执行了相同的查询，并且工作正常.

Note: There is any Problem in the Query, I have executed the same query directly to PHPMyAdmin and it works fine.

推荐答案

有待查询的结果集:

您需要使用/存储结果，然后才能继续下一个查询:由于您似乎并不真正在意第一个结果集，因此请在多次查询之后执行此操作.

You need to use/store result before you can proceed with next query after:Since you look like you don't really care about the first result set, do this after the multi query..

do
{
    $result = mysqli_store_result($connection);
    mysqli_free_result($result);
}while(mysqli_next_result());

另一种选择是关闭连接并重新启动..

Another alternative is to close the connection and starts it again..

mysqli_close($connection);
$connection = mysqli_connect("localhost","username","password","tbl_msgs");

这完全取决于您的要求.

It all depends on your requirements.

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