Python生成矩阵的所有可能组合

问题描述

我需要在Python中生成矩阵的所有组合.输入将是两个整数n和m，我需要生成该矩阵的所有可能状态，并使用1和0作为可能的值.

I need to generate all combinations of a matrix in Python. The input will be two integers n and m, and I need to generate all possible states of that matrix with 1 and 0 as possible values.

例如:

n = 3 m = 2
[[0 0 0] [1 0 0] [1 1 0]
 [0 0 0] [0 0 0] [0 0 0]
 [0 0 0],[0 0 0],[0 0 0] . . . . .
]

给定我直到运行时才知道n和m的值，是否有一种干净有效的方法来执行此操作?使用的最大值为n = 16 m = 16.

Is there a clean and efficient way to do this given I will not know the values for n and m until runtime? The highest value used will be n = 16 m = 16.

推荐答案

一种方法是在列表理解中生成所有长度为 m * n 的二进制序列，并将其重塑为(m，n)在每次迭代中形成嵌套列表.

One way is by generating all binary sequences of length m*n in a list comprehension, and reshaping them into a (m,n) shaped nested list on each iteration.

一种生成所有序列的简单方法是，将 01 的笛卡尔乘积与 n * m 重复，将产生 2 ^(m *n)组合:

A simple way to generate all sequences is by taking the cartesian product of 01 with n*m repeats, which will be produce 2^(m*n) combinations:

from itertools import product
m=3
n=3

x = [[list(i[x:x+m]) for x in range(0, len(i), m)] for i in product("01", repeat=m*n)]

输出

[[['0' '0' '0']
  ['0' '0' '0']
  ['0' '0' '0']]

 [['0' '0' '0']
  ['0' '0' '0']
  ['0' '0' '1']]

 [['0' '0' '0']
  ['0' '0' '0']
  ['0' '1' '0']]
 ...

print(len(x))
# 512

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