本文介绍了根据正则表达式匹配对字符串列表进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个文本文件,看起来像:
I have a text file that looks a bit like:
random text random text, can be anything blabla %A blabla
random text random text, can be anything blabla %D blabla
random text random text, can be anything blabla blabla %F
random text random text, can be anything blabla blabla
random text random text, %C can be anything blabla blabla
当我输入readlines()
时,它变成一个句子列表.现在,我希望此列表按%
之后的字母排序.因此,基本上,将排序应用于上面的内容时,应该看起来像这样:
When I readlines()
it in, it becomes a list of sentences. Now I want this list to be sorted by the letter after the %
. So basically, when the sort is applied to the above, it should look like:
random text random text, can be anything blabla %A blabla
random text random text, %C can be anything blabla blabla
random text random text, can be anything blabla %D blabla
random text random text, can be anything blabla blabla %F
random text random text, can be anything blabla blabla
是否有一个好方法,或者我必须将每个字符串分成小管,然后将字母移动到特定列,然后使用key=operator.itemgetter(col)
进行排序?
Is there a good way to do this, or will I have to break each string in to tubles, and then move the letters to a specific column, and then sort using key=operator.itemgetter(col)
?
谢谢
推荐答案
In [1]: def grp(pat, txt):
...: r = re.search(pat, txt)
...: return r.group(0) if r else '&'
In [2]: y
Out[2]:
['random text random text, can be anything blabla %A blabla',
'random text random text, can be anything blabla %D blabla',
'random text random text, can be anything blabla blabla %F',
'random text random text, can be anything blabla blabla',
'random text random text, %C can be anything blabla blabla']
In [3]: y.sort(key=lambda l: grp("%\w", l))
In [4]: y
Out[4]:
['random text random text, can be anything blabla %A blabla',
'random text random text, %C can be anything blabla blabla',
'random text random text, can be anything blabla %D blabla',
'random text random text, can be anything blabla blabla %F',
'random text random text, can be anything blabla blabla']
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