问题描述
在Swift中，查看字符串是否与模式匹配的简单方法是什么？
In Swift, what is a simple way to see if a string matches a pattern?
伪代码示例：
if string matches pattern ...
if string =~ pattern ...
（我已阅读Swift文档并且没有看到正则表达式功能。我读过有关添加新 =〜运算符这是一个好主意但比我想要的更复杂，因为这是一个教学项目。我试过 rangeOfString 但得到错误：'String'我没有成员'rangeOfString'。我正在寻找一个Swift解决方案，即不输入NSRegularExpression。我不需要对匹配结果数据做任何事情。）
(I have read the Swift docs and haven't seen a regex capability. I've read about adding a new =~ operator which is a good idea yet more complex than I'd like because this is for a teaching project. I have tried rangeOfString but get the error: 'String' does not have a member 'rangeOfString'. I am looking for a Swift solution, i.e. not typing NSRegularExpression. I do not need to do anything with the match result data.)
推荐答案
Swift版本3解决方案：
Swift version 3 solution:
if string.range(of: regex, options: .regularExpression, range: nil, locale: nil) != nil ...
Swift版本2解决方案：
Swift version 2 solution:
if string.rangeOfString(pattern, options: .RegularExpressionSearch) != nil ...
示例 - 执行此字符串包含两个字母o字符？
Example -- does this string contain two letter "o" characters?
"hello world".rangeOfString("o.*o", options: .RegularExpressionSearch) != nil
注意：如果收到错误消息'String'没有成员'rangeOfString'，然后在之前添加： import Foundation 。这是因为
Foundation提供了自动桥接到Swift String类的NSString方法。
Note: If you get the error message 'String' does not have a member 'rangeOfString', then add this before: import Foundation. This is because Foundation provides the NSString methods that are automatically bridged to the Swift String class.
import Foundation
感谢Onno Eberhard对Swift 3的更新。
Thanks to Onno Eberhard for the Swift 3 update.
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