使用Gson的JSON解析

问题描述

我试图用GSON解析一个JSON对象。

我的JSON是：

  
字段  TruncateObj 中的objChild 与它在JSON中的名称不匹配。将字段重命名为 truncate ，然后再试一次。 另外，您可以注释 objChild 字段用 @SerializedName（truncate）告诉gson使用 truncate 字段作为Java对象中的 objChild 字段的值。
 
I am trying to parse a JSON object using GSON. 

My JSON is :
{ "truncate": [
            {
                "lower": 20,
                "upper": 40,
                "delimiter": " ",
                "scope": ["$title"]
            },
            {
                "lower": 30,
                "upper": 65,
                "delimiter": " "
            }
        ] }
I have defined my 2 classes like: 
public class TruncateObj {

    private List<TruncateObjectChild> objChild;

    // getter and setter
}
and 
public class TruncateObjectChild {

    private int lower;

    private int upper;

    private String delimiter;

    private List<String> scope;

// getters and setters
}
My Parsing statement is 
 Gson gson = new Gson();
 TruncateObj truncation = gson.fromJson(template, TruncateObj.class);
For some reason this is not working. Gson creates a TruncatObj child, but the List<TruncateObjectChild> within the TruncateObj is null.
What is wrong in what I am doing?
 解决方案 
The field objChild in your TruncateObj does not match the name it has in the JSON.  Rename the field to truncate and try again.
Alternatively, you could annotate the objChild field with an @SerializedName("truncate") to tell gson to use the value from the truncate field in the JSON as the value for the objChild field in your Java object.
                        
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