问题描述
我在实现中具有以下代码，我想在输出我尝试过的$ text记录之前，先验证是否在表格中插入了1234：
I have this code below in achievement i want to verify if 1234 is inserted in form before output the record in $text i have tried:
$text = "12345678910111213141516171819202121";
$pas = "1234";
if(isset($_POST["subscribe"]))
{
$phone = $_POST["phone"];
if($phone = "$pas")
{
echo $text;
}
if($phone != "$pass")
{
echo erro;
}
}
echo '<form action="#" method="POST">
Your Phone Number <br> <input type="text" name="phone" value="080"/><input type="submit" name="subscribe" value="SEND PAYMENT"/></form></div>';
但是当在表单中提交空或错误的$ pas时，我会在$ text中得到记录。
提前谢谢
but i get record in $text when empty or wrong $pas is submited in the form.Great thanks in advance
推荐答案
这是因为 = 是赋值运算符， == 是相等比较运算符。因此，请尝试以下操作：
This is because = is assignment operator and == is equality comparison operator. So try the following instead:
if($phone == $pas)
{
echo $text;
}
编辑：评论中的问题。输出 html 时应避免 echo ，因此，请尝试以下代码隐藏 submit 按钮，当 $ phone 匹配时。像这样：
Answer to the question in the comment. You should avoid echo when outputing html, So try the following code to hide the submit button when $phone matches. Like:
<?php
$text = "12345678910111213141516171819202121";
$pas = "1234";
if (isset($_POST["subscribe"]))
{
$phone = $_POST["phone"];
if ($phone == $pas)
{
echo $text;
}
if ($phone != "$pass")
{
echo erro;
}
}
?>
<form action="#" method="POST">
Your Phone Number <br />
<input type="text" name="phone" value="080"/>
<?php if(isset($_POST["phone"]) || $_POST["phone"] != $pas): ?>
<input type="submit" name="subscribe" value="SEND PAYMENT"/>
<?php endif; ?>
</form>
这篇关于如何在显示记录之前验证表单输入的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！