在python pickle文件中保存和加载多个对象

问题描述

我有一个类在游戏中为玩家服务，创造他们和其他东西。

I have class that serves players in a game, creates them and other things.

我需要将这些播放器对象保存在文件中以便以后使用。我试过pickle模块，但我不知道如何保存多个对象，并再次加载它们？有没有办法做，或者应该使用其他类，如列表，并保存和加载我的对象在列表中？

I need to save these player objects in a file to use it later. I've tried pickle module but I don't know how to save multiple objects and again loading them? Is there a way to do that or should I use other classes such as lists and save and load my objects in a list?

有更好的方法吗？

推荐答案

tuple或dict是最常用的方法：

Using a list, tuple, or dict is by far the most common way to do this:

import pickle
PIK = "pickle.dat"

data = ["A", "b", "C", "d"]
with open(PIK, "wb") as f:
    pickle.dump(data, f)
with open(PIK, "rb") as f:
    print pickle.load(f)

打印：

['A', 'b', 'C', 'd']

但是，pickle文件任何数量的泡菜。这里的代码产生相同的输出。但请注意，很难写和理解：

However, a pickle file can contain any number of pickles. Here's code producing the same output. But note that it's harder to write and to understand:

with open(PIK, "wb") as f:
    pickle.dump(len(data), f)
    for value in data:
        pickle.dump(value, f)
data2 = []
with open(PIK, "rb") as f:
    for _ in range(pickle.load(f)):
        data2.append(pickle.load(f))
print data2

如果你这样做，你有责任知道你写出的文件中有多少个腌菜。上面的代码通过首先选择列表对象的数量来实现。

If you do this, you're responsible for knowing how many pickles are in the file you write out. The code above does that by pickling the number of list objects first.

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